Excercise 1:
No, this is not simplified fully. The full answer would be <span>−7dk+14d−21k</span>−7, not <span>14d - 9 - 21k - 7dk + 2. So, it is not equivalent.
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Excercise 4:
</span><span>7dk (2 - 3 - 1) - 7
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Just multiply 7dk into (2) (-3) and (-1)
you'd get:
<span><span>−<span>14dk</span></span>+</span>−<span>7 after simplifying it fully.
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p = parameter
w = width
w+2.75
p = 2w+2(w+2.75) = <span>4w</span>+<span>5.5 = 30
Answer to the last one:
w = 6.125</span>
Answer:
2x^1+1
Step-by-step explanation:
Area=L X W
which means that (14x^4+7x^2) needs to be divided by 7x^2
factorise(14x^4+7x^2) which gives 7x(2x^2+1)
divide 7x(2x^2+1) by 7x^2
gives 2x^2 +1
The equation that you are looking for is y = -2x + 3
Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
