In this item, we are informed that the order of the entries does not matter in determination the number of ways in which the Archie can choose for his party. Because the arrangement or order is not important, this type of problem uses the concept of COMBINATION.
The equation for combination is,
nCr = n!/((n - r)!(r!))
nCr is read as "combination of n taken r".
Substituting the known values to the equation,
15C6 = 15! / ((15 - 6)!(6!))
= 5005
Hence, there are 5005 ways in which Archee can choose the 6 entrees for his party.
Answer:
3rd graph down
Step-by-step explanation:
greens are x and carrots are y in my equations
2x - y >= 3
x + 2y < 4
The first equation is solid and will highlight everything to the right of it because it is a >
the second is dashed and will highlight everything to the left of it because it is a <
the only 2 graphs that show this are 1 and 3
looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.
on the first graph the points are (0,4)
plugging those into our equation gives us 0 + 2*4 <4
or 8<4 which doesnt make sense making 3 the correct graph
(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)
Answer: the length is 11 cm.
The width is 7 cm.
Step-by-step explanation:
Let L represent the length of the rectangular plastic box.
Let W represent the width of the rectangular plastic box.
The area of the rectangular top of the box is 77 square cm. This means that
LW = 77- - - - - - - ;- - - -1
The plastic box has a length 4 cm longer than its width. This means that
L = W + 4
Substituting L = W + 4 into equation 1, it becomes
(W + 4)W = 77
W² + 4W = 77
W² + 4W - 77 = 0
W² + 11W - 7W - 77 = 0
W(W + 11) - 7(W + 11) = 0
W - 7 = 0 or W + 11 = 0
W = 7 or W = - 11
Since the width cannot be negative, then W = 7cm
L = 77/7 = 11 cm
A = p(1 + rt)
A/p = 1 + rt
rt = A/p - 1
t = (A/p - 1)/r