Round 3160.9903 to the nearest tenths place

Mathematics

2 answers:

Allisa [31]3 years ago

7 0

That would be:...................

3161.0

motikmotik3 years ago

5 0

The tenths place is right after the decimal point. So, 3160.9903 can be 3160.9.

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If stanley bought a sandwich, that cost $3 with 50% off. what was the original price?

Andrew [12]

Answer:

The answer is 6$. Half of 6$ is 3$

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4 years ago

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For which points in the same quadrant as(2,-10)could Tamara use a number line to find the distance?

VLD [36.1K]

ANSWER

(2,-2)

(10,-10)

(2,-9)

(7,-10)

EXPLANATION

The given point is (2,-10)

This point is in the fourth quadrant.

To be able to use the number line to find the distance between this point , (2,-10) and another point in the fourth quadrant, the second point must have the same x-coordinate with this point or the same y-coordinate with this point.

These points are:

(2,-2)

(10,-10)

(2,-9)

(7,-10)

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3 years ago

1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang

Mandarinka [93]

1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is $\frac{ \sqrt{3} }{2} a$

2. if a a=25 ft, then the height is $\frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7$ (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is $2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}$

so the total area of the roof is $\frac{ \sqrt{3} }{2} a^{2} +3al$

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al

5. so the area now is $\frac{ \sqrt{3} }{2} a^{2} +2al$

6. now a=25 and l=2a=50

Area= $\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2} (\frac{ \sqrt{3} }{2} +4)=625*4.866$

=3041.3 (ft squared)