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Alexxandr [17]
3 years ago
7

The sum of two consecutive integers is 99. Find the value of the smaller integer. (Show work)​

Mathematics
1 answer:
nevsk [136]3 years ago
5 0

Answer:

49.5

Step-by-step explanation:

99/2=49.5

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The slope of the line through -9,6 and -6,-9
Kruka [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
4. Which of the following indicates the multiplication property of equality when solving Vz= 5?
tiny-mole [99]

Answer:

D. 21.

Step-by-step explanation:

The general form of the equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2  where r is the radius.

Comparing:

(x + 5)^2 + (y + 7)^2 = 21^2

So r^2 = 21^2

making r = √21^2

= 21.

plz make me brainliest

3 0
3 years ago
I need help with this..... please help thank you
Papessa [141]

Answer:

option C is the correct answer because the continents used to be part of a larger supercontinent called Pangea and when the continents split the fossils went with it

4 0
3 years ago
Read 2 more answers
Find the circumference of the circle.<br> 7 m
Nutka1998 [239]

Answer:

43.96m is the answer

Step-by-step explanation:

circumference of circle=2πr

=2*3.14*7

=43.96m

8 0
2 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
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