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Alexxandr [17]
3 years ago
7

The sum of two consecutive integers is 99. Find the value of the smaller integer. (Show work)​

Mathematics
1 answer:
nevsk [136]3 years ago
5 0

Answer:

49.5

Step-by-step explanation:

99/2=49.5

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If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes
katrin2010 [14]

Given:

The function is:

y=3x^3-5x^2-11x-3

It is given that -1 is a zero of the given function.

To find:

The other zeroes of the given function.

Solution:

If c is a zero of a polynomial P(x), then (x-c) is a factor of the polynomial.

It is given that -1 is a zero of the given function. So, (x+1) is a factor of the given function.

We have,

y=3x^3-5x^2-11x-3

Split the middle terms in such a way so that we get (x+1) as a factor.

y=3x^3+3x^2-8x^2-8x-3x-3

y=3x^2(x+1)-8x(x+1)-3(x+1)

y=(x+1)(3x^2-8x-3)

Again splitting the middle term, we get

y=(x+1)(3x^2-9x+x-3)

y=(x+1)(3x(x-3)+1(x-3))

y=(x+1)(3x+1)(x-3)

For zeroes, y=0.

(x+1)(3x+1)(x-3)=0

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x=-1 and x=-\dfrac{1}{3} and x=3

Therefore, the other two zeroes of the given function are -\dfrac{1}{3} and 3.

3 0
2 years ago
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