Width = w
length = 11w
Pythagoras theorem
a^2 + b^2 = c^2
Let's say the width is a, the length is b, and the distance between corners (call it d) is c
w^2 + 11w^2 = d^2
Collect like terms,
12w^2 = d^2
Simply
12w = d
You are multiply by 6 each time.
The next term is -216 x 6
-216 x 6= -1296
-1296 is your answer
hope this helps
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
3 is to 12, 5 is to 50, 7 is to 14, and 11 is to 22.
Step-by-step explanation:
