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ElenaW [278]
3 years ago
13

The sum of the first 3 terms of an arithmetic sequence is 21,while their product is 315.determine these 3 terms

Mathematics
2 answers:
Sphinxa [80]3 years ago
4 0
Given: 
Sum of arithmetic sequence is 21.
Product of arithmetic sequence is 315.

I did a manual computation. Arithmetic sequence means that there is a constant difference between the two consecutive numbers.

x + (x+2) + (x + 2 + 2) = 21
3x + 6 = 21
3x = 21 - 6
3x = 15
x = 15/3
x = 5    1st number

x + 2 = 5 + 2 = 7 2nd number

x + 2 + 2 = 5 + 2 + 2 = 9  3rd number.

5 + 7 + 9 = 21
5 x 7 x 9 = 315
liq [111]3 years ago
4 0
These three terms can be written as a-d, a, a+d
Then (a-d)+a+(a+d)=21, i.e. 3a=21 and a=7.
So,
7(7-d)(7+d)=315
7²-d²=315/7=45
d²=49-45=4
d=2 or d=-2.
Thus, we have terms 5,7,9 or 9,7,5.

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▹ Answer

<em>1/3a + c - 7b</em>

▹ Step-by-Step Explanation

(4/3a - 3c - 5b) + (-a - 2b + 4c)

<u>Remove the parentheses</u>

(4/3a - 3c - 5b) + (-a - 2b + 4c)

<u>Rewrite</u>

4/3a - 3c - 5b - a - 2b + 4c

<u>Calculate</u>

1/3a - 3c - 5b - 2b + 4c

<u>Final Answer</u>

1/3a + c - 7b

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