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3 years ago

670.65 which digit is in the tenths place

Mathematics

2 answers:

disa [49]3 years ago

7 0

The answer is the second 6... the one after the decimal place

valina [46]3 years ago

6 0

The five, after the decimal it goes one's then tenths then hundredths

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Which of the following is a solution of x2 + 5x = −2? (2 points) 5 plus or minus the square root of 33 divided by two. 5 plus or

Talja [164]

Answer:

Solutions to the equation are $=\frac{-5+/-\sqrt{17} }{2}$

which agrees with the last option listed among the possible answers

Step-by-step explanation:

We solve this quadratic equation via the quadratic formula:

$x^2+5x=-2\\x^2+5x+2=0\\ \\x=\frac{-5+/-\sqrt{25-4(1)(2)} }{2\,(1)} \\x=\frac{-5+/-\sqrt{17} }{2}$

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4 years ago

Help mee plzz :))tyy

Dimas [21]

Step-by-step explanation:

Given prism has:

Length = 5 in, width = 4 in & height = 6 in

Surface area of prism

$2(lw + wh + lh) \\ = 2(5 \times 4 + 4 \times 6 + 5 \times 6) \\ = 2(20 + 24 + 30) \\ = 2 \times 74 \\ = 148 \: {in}^{2} \\$

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4 years ago

Natalie put 1/3 cup of flour in a bowl. Her sister put another 3/4 cup of flour in the bowl. They need a total of 4 cups of flou

maria [59]

Answer:

2 11/12

Step-by-step explanation:

I know this because you first add 1/3 + 3/4, and that equals 1 1/12. Then, I did 4 - 1/12 and got the answer 2 11/12.

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3 years ago

Hi can someone please help me? :( im not sure where im going wrong. ty!!

lisabon 2012 [21]

The triangle ABC is a right angled triangle , right angled at C because it is the angle subtended by the diameter

Now OA = OB = OC = 4 cm (radii)

AB = OA + OB = 8 cm

By pythagoras theorem ,

$AB^2 - BC^2 = AC^2$

$\sqrt{64 - 16} = AC$

AC =4 $\sqrt3$

shade region area = area of semicircle - area of triangle

= $1/2 \pi r^2$ - 1/2 × base × height

=1/2 × 16 $\pi$ - 1/2 × 4 × $4\sqrt3$

=8 $\pi$ - 8 $\sqrt3$

=8( $\pi - \sqrt3$ )

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3 years ago

Look at the picture!!! Which of the following set of coordinate points are ALL solutions to the given system of inequalities? (0

Elenna [48]

Answer:

soo whats the question

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3 years ago

Read 2 more answers