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3 years ago

ABCD is a rhombus where m∠DAC=4x+9 and m∠DAB=11x−3

Mathematics

2 answers:

Reika [66]3 years ago

8 0

We are given

ABCD is a rhombus

so, firstly , we need to draw diagram

we can see that

diagonal bisects angle

so,

m∠DAB=2*m∠DAC

now, we can plug values

$11x-3=2(4x+9)$

now, we can solve for x

$11x-3=2*4x+2*9$

$11x-3=8x+18$

$11x-3+3=8x+18+3$

$11x=8x+21$

subtract both sides by 8x

$11x-8x=8x-8x+21$

$3x=21$

Divide both sides by 3

we get

$x=7$ ...............Answer

fiasKO [112]3 years ago

5 0

Wow that is hard im not sure what to do but if anything just try your best

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Simplify the expression 6sqrt2/sqrt3

Ilya [14]

The answer would be 2√6 and in decimal form 4.898979, I hope this helps!

8 0

3 years ago

Read 2 more answers

In triangle ABC, AB=10, BC=8, and angle B=30. In triangle KLJ, LJ=20, JK=16, and angle L=30. State whether the triangles are sim

Margaret [11]

Answer:

They are not similar.

Step-by-step explanation:

In triangle ABC, the angle we are given is in between the two defined sides(AB and BC with angle B). If these triangles were similar, we would see this with the SAS postulate.

In triangle KLJ, the angle is not in between the two sides, so they are not similar according to any of these two postulates.

6 0

11 months ago

Find the Area of the figure below, composed of an isoceles trapezoid and one

MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can find the total area dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then

step one

find the area of the isosceles trapezoid using

$A=\frac{a+b}{2}*h$

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

$A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14$

Step two

find the area of the semicircle

the area of a circle is given by

$A_{c}=\pi \frac{d^{2}}{4}\\$

but, we need the area of half circle, we need divide this by 2

$A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}$

now the diameter of the semicircle is 2, put this value into the equation

$A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\$

find the total area

total area= area of the trapezoid +area of the semicircle

$total\ area= 14+\frac{\pi }{2} \\total\ area=15.6$

so, the total area is 15.6 square units

Have a good day.

5 0

3 years ago

i have to make an expression that has a value of 10 out of the numbers 5,2,1,1 and the format it has to go in is like ( - )+( x

soldi70 [24.7K]

Answer:

(1-1)+(5×2)

hope this helps you

6 0

3 years ago

the questipn is: Given segment AB with endpoint (-2,-2) and (8,4), what is the coordinate of the midpoint?

Nataly [62]

Answer:

(3,1)

Step-by-step explanation:

If you plot both of the points on a graph you get another straight line.

When you connect the dots you get 3,1 as the midpoint of the two segments :))

6 0

3 years ago