Question

ABCD is a rhombus where m∠DAC=4x+9 and m∠DAB=11x−3

Answer 1

We are given

ABCD is a rhombus

so, firstly , we need to draw diagram

we can see that

diagonal bisects angle

so,

m∠DAB=2*m∠DAC

now, we can plug values

$11x-3=2(4x+9)$

now, we can solve for x

$11x-3=2*4x+2*9$

$11x-3=8x+18$

$11x-3+3=8x+18+3$

$11x=8x+21$

subtract both sides by 8x

$11x-8x=8x-8x+21$

$3x=21$

Divide both sides by 3

we get

$x=7$...............Answer

Answer 2

Wow that is hard im not sure what to do but if anything just try your best