Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency =
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
Answer:
New bed dimension of bed 0.5 ft, 0.25 ft
New bed dimension of room 1.16 ft, 1.33 ft
Step-by-step explanation:
Given data:
bed dimension is given as 6 ft by 3 ft
room dimension is given as 14 ft 16 ft
according to the given information , new dimension of the room and bed will be 1/12 times of actual dimension. therefore we have
New bed dimension of bed
= 0.5 ft, 0.25 ft
New bed dimension of room
= 1.16 ft, 1.33 ft