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Elis [28]
3 years ago
10

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly

chosen TV commercial will last:
Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

≈0.487

Step-by-step explanation:

I think this is your full question right?

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

Length        Frequency

0-19                   17

20-39               38

40-59                19                    20 to 39 seconds.

60+ 20 to          4

Here is my anwer:

experimental probability = relative frequency = \frac{number of oserved occuerencies}{total number of oserved occuerencies}

Total frequencies = 17 + 38 +18 + 4 = 78

P(20 to 39s) = 38/78 ≈0.487  

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The weight of a product is normally distributed with a mean of four ounces and a variance of .25 squared ounces. What is the pro
ololo11 [35]

Answer:

P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)

And we can find this probability using the complement rule and we got:

P(z>-0.5)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(4,\sqrt{0.25}=0.5)  

Where \mu=4 and \sigma=0.5

We are interested on this probability

P(X>3.75)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)

And we can find this probability using the complement rule and we got:

P(z>-0.5)=1-P(z

5 0
3 years ago
If you can solve all parts I will give brainliest (also give strategy)
Alexxx [7]

The Halloween conical hat, with given height, circular base and brim

extension has the following calculated parameters;

Part a. The slant height is <u>18.2 inches</u>

Part b. The volume of the cone is 37\frac{1}{2}  \cdot \pi in.³

Part c. The area of the brim, <em>A</em> = <u>36·π in.²</u>

Part d. The area of the brim is found by <u>subtracting the area of the base of the cone from the area covered by the perimeter of the brim</u>

Reasons:

Known parameters;

Height of the conical portion, h = 18 inches

Base circumference, C = 5·π inches

Part a. Slant height of the conical portion; Required

Solution:

The circumference of a circle, C = 2·π·r

Therefore;

r = \dfrac{C}{2 \cdot \pi}

Which gives;

r = \dfrac{5 \cdot \pi}{2 \cdot \pi} = \dfrac{5}{2} = 2.5

Radius, r = 2.5 inches

According to Pythagoras's theorem, we have; s² = r² + h²

Where;

s = The slant height of the cone

s² = 2.5² + 18² = 330.25

s = √(330.25) ≈ 18.2

  • The slant height, <em>s</em> ≈ <u>18.2 inches</u>

Part b. The measure in cubic inches of candy that exactly fills the conical portion of the hat is the volume of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h

Therefore;

V = \dfrac{1}{3} \times \pi \times 2.5^2 \times  18 = 37\frac{1}{2}  \cdot \pi

  • The volume of the cone, V = 37\frac{1}{2}·π in.³

Part c. The extension of the brim from the base of the cone = 4 inches

The radius of the brim, R = Radius of the base of the cone + 4 inches

∴ <em>R</em> = 2.5 inches + 4 inches = 6.5 inches

Area of the brim, <em>A</em> = Area of the 6.5 inch circle - Area of the circular base of the cone

∴ A = π × 6.5² - π × 2.5² = 36·π

  • The area of the brim, <em>A</em> = <u>36·π in.²</u>

Part d. The procedure for solving the question in part c, is described as follows;

  • The area of the brim can be found by finding the entire area of the circle formed by the perimeter of the brim, then subtracting the area of the base of the cone from that area.

Learn more here:

brainly.com/question/17023854

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tatuchka [14]
9/3x = 5/8 

Using the reciprocal, multiply each side by 3/9. 

5/8 * 3/9 = 15/72
Simplify it : 5/24

x = 5/24

Hope this helps :)
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-16t2 +64 + 3

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