Question

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

Answer 1

Answer:

≈0.487

Step-by-step explanation:

I think this is your full question right?

Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:

Length        Frequency

0-19                   17

20-39               38

40-59                19                    20 to 39 seconds.

60+ 20 to          4

Here is my anwer:

experimental probability = relative frequency = $\frac{number of oserved occuerencies}{total number of oserved occuerencies}$

Total frequencies = 17 + 38 +18 + 4 = 78

P(20 to 39s) = 38/78 ≈0.487