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zzz [600]
3 years ago
13

The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x)=x^2, which of th

e following could be the equation of G(x)?
A: G(x)=-1/5x^2
B:G(x)=5x^2
C:G(x)=1/5x^2
D:G(x)=-5x^2
Mathematics
2 answers:
Anarel [89]3 years ago
7 0

Answer:Its D

Step-by-step explanation:

vesna_86 [32]3 years ago
5 0
To stretch it vertically, you'll need a coefficient greater than 1 in front of the x. If you want to flip the graph over the x axis that coefficient needs to be negative. So it can only be D
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WILL MARK BRAINLIEST
il63 [147K]

Answer:

1) c 2)c 3)b

Step-by-step explanation:

8 0
3 years ago
Solve for u:−14u+32=−6.
zubka84 [21]

Answer:u=19/7 or 2.714286 or 2 5/7

Step-by-step explanation:

−14u+32=−6

Step 1: Subtract 32 from both sides.

-14u+32-32=-6-32

-14u=-38

Step 2: Divide both sides by -14.

-14u/-14=-38/-14

U=19/7

3 0
2 years ago
Can you please help me fill this out thanks
RoseWind [281]
For perimeter you just add the sides up, so 15+12+9 which = 36
7 0
3 years ago
Read 2 more answers
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
A parallelogram has a base of 4.5 cm and an area of 9.495 cm². Tania wrote the equation 4.5x = 9.495 to represent this situation
Artist 52 [7]

Answer:

The height of the parallelogram is 2.11 cm.

Step-by-step explanation:

Area of the parallelogram is equal to multiplication of base and height.

Given:

Parallelogram has base of 4.5 cm.

Are of the parallelogram is 9.495 cm².

Equation is 4.5x=9.495

Calculation:

(a)

Are of the parallelogram is the product of base length and height of the parallelogram.

Area of the parallelogram is expressed as follow:

A=lh          

Substitute 9.495 cm² for A and 4.5 cm for l in above equation as follows:

9.495=4.5h             …… (1)

Now relate the equation (1) and given equation. So, here x is nothing but the height of the parallelogram.

(b)

From equation (1), height of the parallelogram is calculated as follows:

9.495=4.5h

h=\frac{9.495}{4.5}

h=2.11 cm

Thus, the height of the parallelogram is 2.11 cm.

5 0
2 years ago
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