Answer:
Yes
Step-by-step explanation:
They are parallel lines basically, ingnore the measurements and the traingle, they were put there to confuse you.
Hope this helps
Never30
11) First, add 74 and 43.
74+43=117
Subtract 117 from 180. Do this because this will give you the value of angle 1. This is because the sum of the angles in a triangle will always add up to 180 degrees.
180-117=63
Angle 1 = 63 degrees
Angle 2 also equals 63 degrees, because they are vertical angles.
Angle 2= 63 degrees
Now, add 63 and 79
63+79=142
Subtract 142 from 180
180-142=38
Angle 3 = 38 degrees
12)
First, subtract 56 from 180. Do this to find angle C. They are supplementary angles, so they will equal 180 degrees.
180-56=124
Angle C=124 degrees
Now, add 124 and 20
124+20=144
Finally, subtract 144 from 180
180-144=36
The measure of angle A is 36 degrees
Hope this helped! :)
Answer:
m = (y - y)/(x - x)
Rise/run
Step-by-step explanation:
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
Game 2
Step-by-step explanation:
Each hit the points would double (point(x2))
Example:
1x2=2, 2x2=4, 4x2=8, 8x2= 16, 16x2=32, and so on.
