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2 years ago

Y=2x+1

Mathematics

1 answer:

yan [13]2 years ago

3 0

Answer:

(1) 2 (2) (-1/2,0) (3) (0,1)

Step-by-step explanation:

The slope of the line is the number times x. This equation is y=mx+b, where m is the slope and b is the y-intercept. In this case, m is 2, so we have our slope. The y-intercept is easy, as we already know it to be (0,1). The x-intercept is the point where the line hits x when y=0. To solve for the x-intercept, we set y to 0 and solve. We have 0=2x+1. First, we subtract 1 from both sides and get -1=2x. Next, to get x by itself, divide both sides by 2. Now we have -1/2=x. Now we have our x coordinate for our x-intercept. Because of this, we get (-1/2,0) as our x-intercept.

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Can somebody help me out

Alex_Xolod [135]

First one is C (18 sq units)

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2 years ago

Will give brainliest A ? B? C ?

dolphi86 [110]

Answer:

A: 180° B: 360° C: 540°

Step-by-step explanation:

A: The measures of interior angles of a triangle sum to 180°. Since figure ABC is a triangle, the interior angles of figure ABC sum to 180°.

B: We can see the quadrilateral ACDE is a trapezoid. If you can see, the trapezoid can be split into two triangles if you connect points C and E. As U mentioned before, the measures of interior angles of a triangle sum to 180°. Since we know figure ACDE can be split into two triangles we have to do: 180x2 which is 360°.

C: Now that we know the Pentagon ABCDE can be split into 3 triangles(1 from figure ABC and 2 from figure ACDE), we have to multiply 180 by 3 because like I mentioned before, the measures of interior angles of a triangle sum to 180°. So, 180x3=540°.

5 0

2 years ago

Read 2 more answers

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

2 years ago

Please help me!! (x+5) (x-2) Any work out or help would be appreciated!! Thanks! :)

Lostsunrise [7]

Answer:

Step-by-step explanation:

If you treat (x+5) as a single value and (x-2) as the values of x and +2, you can distribute (x+5) to x and +2: ( (x-5)*x + (x-5)*2 ). Then you can treat x-5 as the values of x and -5 and distribute those to the numbers next to them: (×^2 - 5x) + (2x - 10). This results in x^2 -3x - 10.

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3 years ago

What is the word pharse for y/5

Vitek1552 [10]

I'm pretty sure it's y divided by 5 because the fraction bar means divided by

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2 years ago