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3 years ago

Analyze the asymptotes of the function.

Mathematics

1 answer:

koban [17]3 years ago

5 0

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

Step-by-step explanation:

$y=\frac{1}{x+1}$

To find vertical asymptote we set the denominator =0 and solve for x

x+1=0 (subtract 1 from both sides)

x=-1

So, vertical asymptote at x=-1

To find horizontal asymptote we look at the degree of both numerator and denominator

there is no variable at the numerator , so degree of numerator =0

degree of denominator =1

When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

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tigry1 [53]

Hello from MrBillDoesMath!

Answer:

5, 10, 0

Discussion:

Let "f" be the first number. Then the questions tells us that

f + 2f + (f-5) = 15 =>

f + 2f + f - 5 = 15 => add 5 to both sides

4f = 5+ 15 = 20 => divide both sides by 4

f = 20/4 = 5

The numbers as

f: 5

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(f-5): 0

Thank you,

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2 years ago

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Notice the picture below

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3 years ago

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3 years ago

What is the area of a triangle with vertices (3,0) (9,0) (7,6)

Nezavi [6.7K]

Answer:

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Step-by-step explanation:

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