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Wewaii [24]
3 years ago
12

1.33 equals .002 divided by 6A. Solve for A?

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
Hey Tyler

1.33 = 0.002/6a
Cross multiply
1.33(6a) = 0.002
7.98a = 0.002
Divide both sides by 7.98
7.98a/7.98 = 0.002/7.98
a = 0.000251

I hope I helped!
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So basically you do two of the equations first and then solve for the last equation. Please Refer To The Picture



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Step-by-step explanation:

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3 years ago
John and Ariana bought school supplies, John spent $10.65 on 4 notebooks and 5 pens. Ariana spent $7.50 on 3 notebooks and 3 pen
timurjin [86]

Cost of 1 notebook is $ 1.85 and cost of 1 pen is $ 0.65

<h3><u>Solution:</u></h3>

Let "a" be the cost of 1 notebook

Let "b" be the cost of 1 pen

Given that John spent $10.65 on 4 notebooks and 5 pens

cost of 1 notebook x 4 + cost of 1 pen x 5 = 10.65

4a + 5b = 10.65 ------ eqn 1

Given that Ariana spent $7.50 on 3 notebooks and 3 pens

3a + 3b = 7.50 ----- eqn 2

Let us solve eqn 1 and eqn 2 to get the values of "a" and "b"

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12a + 15b = 31.95  ---- eqn 3

Multiply eqn 2 with 4

12a + 12b = 30 ------ eqn 4

Subtract eqn 4 from eqn 3

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12a + 12b = 30

(-) ---------------------

3b = 1.95

b = 0.65

Substitute b = 0.65 in eqn 1

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8 0
3 years ago
Determine if events A and B are mutually exclusive.
Airida [17]

Answer:This is mutually exclusive

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Step-by-step explanation:

6 0
3 years ago
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For the given function, find the vertical and horizontal asymptote(s) (if there are any). f(x) = the quantity x squared plus fou
Vika [28.1K]

Answer:

Vertical asymptote at x= 6

Oblique asymptote at y=x+10

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Vertical asymptote at x= 6

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Here,  the degree of numerator is higher than the degree of denominator. So there will be a slant  or oblique asymptote. we can find it by long division.

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                      -------------------------------

      x-6              x^2  +  4x  -3

                         x^2  - 6x

                     -------------------------------(subtract)

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Oblique asymptote at y=x+10



3 0
4 years ago
Read 2 more answers
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