Question

A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t) = 40t – 5tÆ, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?

Answer 1

at t = 5:

x(5) = 100
y(5) = 200 - 25
       = 175

$\frac{y(5)}{x(5)}$ = $\frac{175}{100}$ = 7/4

Answer 2

It would be 4958 divided by 8 aand