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katen-ka-za [31]
3 years ago
12

Which of the following is the equation of an ellipse centered at (5,1) having a vertical minor axis of length 4 and a major axis

of length 6?
Options are in image

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Any ellipse has the following equ

ation:

\frac{ {x}^{2} }{ {a}^{2} }  +  \frac{ {y}^{2} }{ {b}^{2} }  = 1

where

  • 2b = vertical axis length
  • 2a = horizontal axis length

(as in the picture)

So it should be like:

\frac{ {x}^{2} }{ { (\frac{6}{2} )}^{2} }  +  \frac{ {y}^{2} }{ {( \frac{4}{2} )}^{2} }  = 1 \\  \frac{ {x}^{2} }{ 9}  +  \frac{ {y}^{2} }{ 4 }  = 1

Since it should be moved to the right and up, the answer would be:

\frac{ {(x - 5)}^{2} }{ 9}  +  \frac{ {(y - 1)}^{2} }{ 4 }  = 1

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A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
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