Answer:
Option D 
Step-by-step explanation:
In this problem we have a exponential function of the form

where
F(x) -----> the rabbit population
x ----> the number of weeks
a is the initial value
b is the base
In this problem we have
a=150 rabbits
b=1-r
r=15%=15/100=0.15
so
b=1-0.15=0.85
substitute the values

Answer:
= 9
Step-by-step explanation:
Given that,
Asn expression : 
We need to evaluate the above expression.
We know that, 
So,

or

So, the value of
is 9. Hence, the correct option is (b).
Answer:
C. m ≥ 9
Step-by-step explanation:
7m -2 ≥ 61
7m ≥ 61+2
7m ≥ 63
m ≥ 63/7
m ≥ 9
Answer:
x-6 <1
Step-by-step explanation:
Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....