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erma4kov [3.2K]
3 years ago
10

Solve (x-4)^2=25 What method was used?

Mathematics
2 answers:
Serhud [2]3 years ago
5 0
(x - 4)² = 25
x - 4 = \pm √25
x - 4 = \pm 5
x = 5 + 4 or x = -5 + 4
x = 9 or x = -1

Method Use : Completing the square

-------------------------------
Answer: x = 9 or x = -1
-------------------------------

Degger [83]3 years ago
3 0
When trying to solve for a variable a good place to start is to think about what was done to it. (Use PEDMAS)

In this problem:
1st: 4 was subtracted from x
2nd: x was squared

So to solve for x undo what was done to it. So do to x the opposite of what was done to it, but in reverse order. (Remember what you do to one side of the equal sign you have to do to another).

In this problem:
1st: square root x and square root 25 (this cancels out the square)
2nd: add 4 to x and add 4 to 25 (this cancels out the -4)

So simplified:
(X-4)^2=25
(X-4)=5
X=9
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6 0
3 years ago
Find the range of the function for the given domain.
Alenkasestr [34]
<h3>Answer:  D.  {-12, -9, -6, -3, 0}</h3>

=================================================

Explanation:

The domain is the set of allowed x inputs. The range is the set of possible y outputs.

The set {-2,-1,0,1,2} represents all the possible x inputs

Let's plug each of those into the equation y = 3x-6 to find the corresponding paired out puts.

Note: y = f(x), so f(x) = 3x-6 is the same as y = 3x-6.

---------------

If x = -2, then,

y = 3x-6

y = 3(-2)-6

y = -6-6

y = -12

We see that x = -2 and y = -12 pair up together.

The value -2 in the domain maps to -12 in the range.

----------------

If x = -1, then,

y = 3x-6

y = 3(-1)-6

y = -3-6

y = -9

The input x = -1 in the domain maps to the output y = -9 in the range

So far the range consists of {-12, -9} in either order.

The answer is between A and D

-----------------

If x = 0, then,

y = 3x-6

y = 3(0)-6

y = 0-6

y = -6

So -6 is also part of the range. We have {-12, -9, -6} so far. The answer is still between A and D.

------------------

If x = 1, then,

y = 3x-6

y = 3(1)-6

y = 3-6

y = -3

The range updates to {-12, -9, -6, -3}

A and D are still equally valid

-------------------

We have one more x value to try

If x = 2, then,

y = 3x-6

y = 3(2)-6

y = 6-6

y = 0

Since y = 0 is in the range, instead of y = 1, this rules out choice A

The answer is therefore D.  {-12, -9, -6, -3, 0}

8 0
3 years ago
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VikaD [51]
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6 0
4 years ago
What’s 18/1 as a mixed number
Alina [70]

Answer:

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Step-by-step explanation:

18 over 1 is still 18. It shouldn't be a mixed number

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3 years ago
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Answer:

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