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3 years ago

15

Help me please I don’t know what the answer is

1 answer:

Anon25 [30]3 years ago

5 0

I believe that B) m<3 would need to double. Since m<6 and m<3 are corresponding angles, they are always equal. So if 6 doubles, 3 needs to as well in order to be equal.

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HELP MEEEEE EASY DUE IN A MINSS<br> What is the prime factorization of 990?

alex41 [277]

Answer:

11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.

Step-by-step explanation:

3 0

3 years ago

Given f(x) = 2^x and g(x)=x+1, (fog)(x)=

mixas84 [53]

Answer:

(f ￮ g)(x) = $2^{x+1}$

Step-by-step explanation:

Substitute x = g(x) into f(x) , that is

(f ￮ g)(x)

= f(g(x))

= f(x + 1)

= $2^{x+1}$

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3 years ago

Read 2 more answers

HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?

Shkiper50 [21]

We need to simpify the given expression. The given expression to us is ,

<u>Given </u><u>Expression</u><u> </u><u>:</u><u>-</u><u> </u>

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }$

<u>Using </u><u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>

$\sf\implies \red{ sin^2\theta + cos^2\theta = 1}$

<u>So </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

$\sf\implies - sin^2\theta = cos^2\theta -1$

<u>We </u><u>have</u><u> </u><u>:</u><u>-</u><u> </u>

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}$

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>-</u><u>1</u><u>/</u><u>4</u><u>. </u>

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3 years ago

Naomi made a triangular pyramid from cardboard. The triangular base has a height of 4 inches and a base length of 15 inches. The

Thepotemich [5.8K]

Answer:

She can double the base length of the base so that the new volume is 120 cubic inches

Step-by-step explanation:

3 0

3 years ago

6th grade math lol

nikdorinn [45]

Answer:

A. 30 for everyone in class | B. 12 Boys in the class

Step-by-step explanation:

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3 years ago