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3 years ago

I suck at this type of math because the teacher did not explain good enough and I’m stuck.

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

6 0

Answer:

Step-by-step explanation:

2^2+b^2=5^2

4+b^2=25

b^2=21

Red

kondor19780726 [428]3 years ago

6 0

Answer:

Step-by-step explanation:

2^2+b^2=5^2

4+b^2=25

b^2=21

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-3x^{2}-21x-54 what are the zeros? (Solutions)

Irina-Kira [14]

The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

x^2+7x+18
a=1
b=7
c=18

x= $\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}$
x= $\frac{-7+/- \sqrt{49-72} }{2}$
x= $\frac{-7+/- \sqrt{-23} }{2}$
i=√-1
x= $\frac{-7+/- i\sqrt{23} }{2}$

the zerose would be
x= $\frac{-7+ i\sqrt{23} }{2}$ or $\frac{-7- i\sqrt{23} }{2}$

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3 years ago

Find the least common multiple of: 12x^3y^2 and 15x^2y^5

allochka39001 [22]

Answer: $60x^3y^5$

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: $12x^3y^2$ and $15x^2y^5.$

Since, $12x^3y^2=2\times2\times3\times x^3y^2$

$15x^2y^5=3\times5\times x^2y^5$

The least common multiple of: $12x^3y^2$ and $15x^2y^5.$ = $2\times2\times3\times5\times x^3y^5=60x^3y^5$ [take highest power of x and y ]

Hence, the least common multiple of: $12x^3y^2$ and $15x^2y^5.$ = $60x^3y^5$

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The total you will pay for interest and loan amount is $749.07

iStep-by-step explanation:

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