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Naddika [18.5K]
3 years ago
9

27)

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

A). No triangle.

Step-by-step explanation:

In order to construct a triangle the sum of any 2 sides must be greater than the third side.

Here 5 + 8  ( =13) is less than the 3rd side, which has a length of  15.

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Hi! How do you solve this? Step by step??
Mars2501 [29]

Answer:

30

Step-by-step explanation:

Substitue 3 for every x in the equation

10(3)-(3*3)(2*3)+(3)^2(2*3)

Multiply

30-(9)(6)+9(6)

30-54+54=30

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Can i have a z score that extends past -0.5 or +5.0
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Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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Paladinen [302]

Answer:

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Step-by-step explanation:

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Answer:

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