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RSB [31]
3 years ago
15

Felix wrote several equations and determined that only one of the equations has no solution. Which of these equations has no sol

ution?
3(x-2)+x=4x+6

3(x-2)+x=4x-6

3(x-2)+x=2x-6

3(x-2)+x=3x-3
Mathematics
2 answers:
lozanna [386]3 years ago
6 0
A. 3(x-2)+x=4x+6 has no solution.
pantera1 [17]3 years ago
3 0

Answer:

Equation 1 has no solution.

Step-by-step explanation:

We are given the following information in the question:

We evaluate the given expressions to find which equations have no solution.

1)

3(x-2)+x=4x+6\\3x -6 + x= 4x + 6\\4x - 6 = 4x + 6\\-6 = 6\\\text{which is not possible}\\\text{The above equation has no solution}

2)

3(x-2)+x=4x-6\\3x -6 + x= 4x - 6\\4x - 6 = 4x - 6\\\text{The above equation has infinitely many solutions}

3)

3(x-2)+x=2x-6\\3x -6 + x= 2x - 6\\4x - 6 = 2x - 6\\2x = 0\\x = 0\\\text{The above equation has unique solution}

4)

3(x-2)+x=3x-3\\3x -6 + x= 3x - 3\\4x - 6 = 3x - 3\\x = 3\\\text{The above equation has unique solution}

Equation 1 has no solution.

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Step-by-step explanation:

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Step-by-step explanation:

The standard form of a polynomial is the descending order, that means that it must be written according from its higher power, down straight to the coefficient with no variable.

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