1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ganezh [65]
3 years ago
10

Is 2× 17 5/6 greater than or less than 36

Mathematics
2 answers:
jonny [76]3 years ago
4 0

Answer:

less than

Step-by-step explanation:

.

emmainna [20.7K]3 years ago
3 0

Answer:

<h3>Less Than</h3>

Step-by-step explanation:

Explanation:

Either or from what I typed, the equation 2 x 17 5/6  is less than 36. The equation and solutions are shown from below.

Equation:

2 * 17 * (5/6) > 36

34 (5/6) > 36

28.3333 > 36 <= This is not true

If I have mistyped your question,

2 * 17(5/6) > 36

2(14.1666.. ) >36

Around 28.3332 > 36 <= Also not true

<h2>Make sure to make me the brainliest answer! It will be greatly appreciated</h2>
You might be interested in
Help pls!
4vir4ik [10]

Answer:

the probability that the next gumball that comes out will be neither yellow nor blue = 6/17

Step-by-step explanation:

neither yellow nor blue gumball = pink gumball = 6

3 yellow + 8 blue + 6 pink = total =17

3 0
3 years ago
Which answer describes the transformation of f(x)=x2−1 to g(x)=(x+2)2−1 ?
notsponge [240]
That would be the second choice. Translation of 2 to the left
4 0
2 years ago
Read 2 more answers
Plz don't answer unless you will do all ty
liberstina [14]
The answer would be D
7 0
3 years ago
A construction worker is sent to the store to buy more than 30 lb of roofing nails. The nails are sold in 5 lb boxes and 10 lb b
trapecia [35]

Answer:

The answer is A: 5x + 10y > 30. That is, the combination of boxes must be greater than 30 since the requirement is to have more than 30 lb of nails.

Step-by-step explanation:

The worker can buy a combination of boxes, as long as the total is greater than 30 lb. Multiply 5 lb by x and add that to 10 lb times y to get the total, which must exceed 30 lb.

8 0
2 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
Other questions:
  • What equation matches the table of values
    11·1 answer
  • Kevin can carry a basket 5 feet Rachel can carry it three feet farther than Kevin Daniel can carry the basket half as far as Rac
    7·1 answer
  • Cat face 5 la puterea 19
    9·1 answer
  • A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimate
    11·2 answers
  • Help me please :( !
    9·2 answers
  • When doing blood testing for a viral infection, the procedure can be made more efficient and less expensive by combining partial
    9·1 answer
  • What is the difference between online school and in-person
    13·2 answers
  • Check whether the sequence is arithmetic. If​ so, find the common difference d. 2​, 7​, 12​, ​17, 22 ... Select the correct choi
    7·1 answer
  • David drove 580 km on 7 hour journey. on the city roads he drove 60km/h and on the he drove 100km/h. How long did he drive at ea
    5·1 answer
  • 6.7.37
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!