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Andre45 [30]
3 years ago
13

Find the error in the problem.

Mathematics
2 answers:
Sonbull [250]3 years ago
5 0
The 2nd step, you're supposed to combine like terms (20h and 2h) but not the 5 because it doesn't have a h next to it.
Keith_Richards [23]3 years ago
4 0
They didn’t combine like terms. They should have combined 20h+2h before continuing to the next step.
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Help! Find the answers pleaseeeeee
OleMash [197]

Answer:

Step-by-step explanation:

area of rectangle=20×11=220 sq. cm.

area  of circle=π×4²=16π≈50.27 sq.cm

area of remaining rectangle=220-50.27≈169.73 sq.cm.

4 0
3 years ago
Read 2 more answers
What is the answer I really need help
attashe74 [19]

Answer: 27

Step-by-step explanation:

The perimeter is the lengths of all sides of the figure added together. Since all  sides are equal in this triangle, we know all sides have a length of 9. We know this because all sides have 2 little lines on them, symbolizing that they are equal.

P=9+9+9=27

5 0
3 years ago
What is the answer to 15g+18=
taurus [48]

Answer:-18/15

Step-by-step explanation:

15g+18=0

15g=-18

divide both sides by 15

g=-18/15

8 0
3 years ago
Which value is NOT a solution of 8x3 – 1 = 0?
Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Step-by-step explanation:

Considering the equation

8x^3\:-\:1\:=\:0

Steps to solve the equation

8x^3-1=0

\mathrm{Add\:}1\mathrm{\:to\:both\:sides}

8x^3-1+1=0+1

\mathrm{Simplify}

x^3=\frac{1}{8}

\mathrm{Divide\:both\:sides\:by\:}8

\frac{8x^3}{8}=\frac{1}{8}

\mathrm{Simplify}

x^3=\frac{1}{8}

As

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}

So,

x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}

Therefore,

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Keywords: solution, value

Learn more about equation solution from  brainly.com/question/1679491

#learnwithBrainly

7 0
3 years ago
Common factors of 28 and 40
Nady [450]
28: 1, 2, 4, 7, 14, 28

40: 1, 2, 4, 5, 8, 10, 20, 40

The common factors are 1, 2, and 4.

You can use a factor rainbow to help you find the factors (:
7 0
3 years ago
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