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3 years ago

Find the error in the problem.

Mathematics

2 answers:

Sonbull [250]3 years ago

5 0

The 2nd step, you're supposed to combine like terms (20h and 2h) but not the 5 because it doesn't have a h next to it.

Keith_Richards [23]3 years ago

4 0

They didn’t combine like terms. They should have combined 20h+2h before continuing to the next step.

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The probability that it will snow on the last day of January is 85%. If the probability remains the same of the first eight day

MrRa [10]

Answer:

Here, we have:

P(5 days snow in this 8 days) = 8C5 x (0.85)^5 x (1 - 0.85)^3 = 0.084

P(6 days snow in this 8 days) = 8C6 x (0.85)^6 x (1 - 0.85)^2 = 0.238

P(7 days snow in this 8 days) = 8C7 x (0.85)^7 x (1 - 0.85)^1 = 0.385

P(8 days snow in this 8 days) = 8C8 x (0.85)^8 x (1 - 0.85)^0 = 0.272

Add up those above, then the probability that it will snow AT LEAST five of those days in February:

P = 0.084+ 0.238 + 0. 385 + 0.272 = 0.979

Hope this helps!

5 0

3 years ago

PLEASE HELP!!! <br> WHICH OF THE FOLLOWING FUNCTIONS IS GRAPHED BELOW?

SashulF [63]

Answer: D.

Step-by-step explanation:

For an absolute value function, the vertex of $f(x) = |x+h| + k$ is defined as the point (-h, k) for the coordinate (x, y).

When x is equal to negative h, the value for x and value for h effectively cancel out, and only the positive k remains, hence the vertex being (-h, k).

The function given has a vertex at (2, 3). We know that the vertex of an absolute function is (-h, k), so h must equal -2 and k must equal 3.

The equation:

$f(x) = |x-2| + 3$

7 0

3 years ago

Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric

quester [9]

I'm guessing S^20 is actually referring to the 20th partial sum $S_{20}$ , with

$S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)$

in the arithmetic case, and

$S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}$

in the geometric case.

(a) Combining like terms, we have

$S_{20}=20+0.1(1+2+\cdots+18+19)$

and invoking the formula

$1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2$

we end up with

$S_{20}=20+0.1\dfrac{19\times20}2=39$

(b) Multiply $S_{20}$ by 1.1, then subtract this from $S_{20}$ :

$1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}$

$S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}$
$\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275$

7 0

2 years ago

How many triangles can be constructed with side lengths 5, 7, and 15?

IrinaVladis [17]

More than ne triangle

5 0

3 years ago

Read 2 more answers

Write an<br> expression to represent:<br> The sum of ten and the quotient of a number and 6.

hoa [83]

Answer:

10 + x/6