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3 years ago

Jane travels

Mathematics

1 answer:

Amanda [17]3 years ago

6 0

Kevin traveled at 19 miles/ hour, and Jane traveled at 76 miles/hour.

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Terry earns $10 per hour at Big Bob's Burgers. Jill earns 20% less than Terry and Jerry earns $0.50 more per hour than Jill. Whi

trapecia [35]

The answer to this question is

h=8.50h
h is the amount of hours.

Hope This Helps!
Have A Great Day!
:D

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3 years ago

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A circle is defined as having 360°. How could that information become useful when you start to inscribe triangles in circles?

ivolga24 [154]

Triangles are defined as having 180°.

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3 years ago

Find all solutions to the equation. -\dfrac{2}{x(x+2)}=\dfrac{x+3}{x+2}− x(x+2) 2 = x+2 x+3 minus, start fraction, 2, divide

Gnoma [55]

Answer:

$x=-1$

Step-by-step explanation:

We have been given an equation $\frac{-2}{x(x+2)}=\frac{x+3}{x+2}$ . We are asked to find the solutions of our given equation.

First of all, we will cross multiply our given equation as:

$-2(x+2)=x(x+2)(x+3)$

Subtract $x(x+2)(x+3)$ from both sides:

$-2(x+2)-x(x+2)(x+3)=x(x+2)(x+3)-x(x+2)(x+3)$

$-2(x+2)-x(x+2)(x+3)=0$

Now we will factor out $(x+2)$ .

$(x+2)(-2-x(x+3))=0$

$(x+2)(-2-x^2-3x)=0$

$(x+2)(-(x^2+3x+2))=0$

Now we will factor by splitting the middle term.

$-(x+2)(x^2+2x+x+2)=0$

$-(x+2)(x+2)(x+1)=0$

$-(x+2)^2(x+1)=0$

Now we will use zero product property and solve for x as:

$-(x+2)^2=0,(x+1)=0$

$(x+2)=0,(x+1)=0$

$x=-2,x=-1$

Now, we will check for extraneous solutions.

We can see that $x=-2$ will make both denominators zero because our function is not defined at $x=-2$ .

Therefore, the solution for our given equation is $x=-1$ .

7 0

4 years ago

Read 2 more answers

Solve 6(2/3x-3)>8. The thing says the question is too short and to add at least 20 more words so ignore this sentence, it's o

xxTIMURxx [149]

Answer:

$6(\frac{2x}{3} -3) > 8\\$

Solve brackets

6(0.66x-3)>8

Multiply 6 with values in the bracket

So, 6x0.66x and 6x-3

4x- 18> 8

Since 4x and 18 are unlike terms, we will take 18 onto the other side, thus:

4x>8+18

4x>26

Now to find the value of x, divide 4 on B.S

x> $\frac{26}{4}$

X> 6.5

OR in 'fraction form'

X> $\frac{13}{2}$

Hope this helps :D

5 0

2 years ago

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How do I solve this equation and check the solutions?

bearhunter [10]

Answer:

{-6}

Step-by-step explanation:

Step 1 Raise both sides of the equation to the index of the radical in the case 2

$(\sqrt{2x+13} )^{2} =(x+7)^{2}$

$2x + 13 = (x+7)(x+7)$

$2x +13 = x^{2} + 14x + 49\\0=x^{2} +12x+36$

Step 2 Factor

(x + 6)(x + 6) = 0

x + 6 = 0

x = - 6

Step 3 Check -6

$\sqrt{2(-6)+13} = -6 + 7\\\sqrt{-12+13} = 1\\\sqrt{1} = 1\\1 = 1$

5 0

3 years ago