The effective annual interest rate is:
i = (1 + 0.064/12)^12 - 1 = 0.066
In year 1: the interest is $613.80 (multiple $9300 by 0.066)
In year 2: the interest is $654.31 (add interest from year 1 to $9300 and multiply by 0.066)
In year 3: the interest is $656.98 (do the same as year 2)
In year 4: the interest is $657.16
The total interest is: $2582.25
The present worth of this amount is:
P = 2582.23 / (1 + 0.066)^4 = $1999.72
The answer is $1999.72.
4x-24y. Basically you distribute 4 to x which makes it 4x and distribute 4 to 6 which multiplies to 24 and you drop y next to it making it 24y
A) ![Probability =0.297](https://tex.z-dn.net/?f=Probability%20%3D0.297)
B)In 200 times he can hit 59 times !
<u>Step-by-step explanation:</u>
Here we have , A baseball player got a hit 19 times in his last 64 times at bat. We need to find the following :
a. What is the experimental probability that the player gets a hit in an at bat?
According to question ,
Favorable outcomes = 19
Total outcomes = 64
Probability = (Favorable outcomes)/(Total outcomes) i.e.
⇒ ![Probability = \frac{19}{64}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B19%7D%7B64%7D)
⇒ ![Probability =0.297](https://tex.z-dn.net/?f=Probability%20%3D0.297)
b. If the player comes up to bat 200 times in a season, about how many hits is he likely to get?
According to question , In 64 times he hit 19 times . In 1 time there's probability to hit 0.297 times! So ,In 200 times he can hit :
⇒ ![Hit =0.297(200)](https://tex.z-dn.net/?f=Hit%20%3D0.297%28200%29)
⇒ Hit = 59.36
Therefore , In 200 times he can hit 59 times !
Answer:
0.67>2/3
Step-by-step explanation:
If you divide 2 by 3, you will end up with 0.6.
Now, you can compare the two numbers 0.6 and 0.67.
Answer:
x
=
26
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.