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2 years ago

Linear System, substitutional method 5x+4y=32 9x-y=33 helppp

1 answer:

6 0

5x + 4y = 32 ⇒ 45x + 36y = 288
9x - 1y = 33 ⇒ 45x - 5y = 165
 41y = 123
 41 41
 y = 3
 5x + 4(3) = 32
 5x + 12 = 32
 - 12 - 12
 5x = 20
 5 5
 x = 4
 (x, y) = (4, 3)

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A group of students goes out to lunch. If two have burritos and five have tacos, the bill will be $19.50. If five students have

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The price of the burrito is $3.5 and the price of the taco is $2.5.

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The market and Stock J have the following probability distributions:

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Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

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And the variance would be given by:

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And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

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And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

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2 years ago