T1 + t2 = 2h and 30min;
t1 * 600 = t2 * 400 => t2 = (3/2) * t1;
then, t1 + (3/2) * t1 = 2h and 30min => 2t1 + 3t1 = 5h => 5*t1 = 5h => t1 = 1h => t2 = 1h and 30 min;
The distance is 2 * 1 * 600 = 1200miles;
Answer:
Try as percentages so
7) 37.5%
8) 50%
9) 12.5%
10) 62.5%
11) 87.5%
12) 50%
13) 62.5%
14) 37.5%
15) 100%
Step-by-step explanation:
Answer:
Option A
Step-by-step explanation:
Given that A linear model is given for the data in the table: y=1.25x+2.
Let us write observed values for each x and also the predicted values as per equation.
x 2 3 4 8 10 16 20 24 Total
y((O) 3 4 7 12 16 22 28 30
y(P) 4.5 5.75 7 12 14.5 22 27 32
DEv 1.5 1.75 0 0 1.5 0 1 2 7 75
where y(0) represents observed y or y in the table given
y(P) gives values of y predicted as per the equation 1.25x+2
Dev represents the absolute difference
Hence answer is option
A.7.75
Answer:
x-2
The choose (1)
Step-by-step explanation:
(x³-3x²+3x-2)÷(x²-x+1)
(x-2)(x²-x+1) ÷ (x²-x+1)
Delete (x²-x+1)
so = (x-2)
