If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:
(true for <em>y</em> between -π/2 and π/2)
Now take the derivative of both sides and solve for it:
What is the solution set for 5x−5=15, given the replacement set {0, 1, 2, 3, 4}?
2 answers:
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Hello!
Answer:
To solve, we will need to use Right-Triangle Trigonometry:
Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)
tan ∠S = a / (1/2b)
tan ∠S = 3√5 / 14
tan ∠S ≈ 0.479
arctan 0.479 = m∠S (inverse)
m∠S and m∠R ≈ 25.6°
Use cosine to solve for the hypotenuse, or the missing side-length:
cos ∠S = 14 / x
x · cos (25.6) = 14
x = 14 / cos(25.6)
x ≈ 15.52
Both triangles are congruent, so we can go ahead and find the perimeter of the figure:
RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.
Hope this helped you! :)
