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3 years ago

A light bulb consumes 3600 watt-hours per day. How long does it take to consume 18900 watt-hours?

Mathematics

2 answers:

Pie3 years ago

5 0

Answer

5 days and six hours or 126 hours

Lelu [443]3 years ago

3 0

Answer:

5 days and 6 hours, or atlwast I think

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McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine

jonny [76]

Answer:

$t _{critical} = 1.760$

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

$H_o: \mu_1 - \mu_2 = 0$

Alternative hypothesis;

$H_a : \mu_1 - \mu_2 > 0\\$

The pooled variance t-Test would have been determined if the population variance are the same.

$S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}$

$S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}$

$S_p^2 = 7.14$

The t-test statistics can be computed as:

$t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}$

$t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}$

$t= \dfrac{3}{1.336}$

t = 2.2450

Degree of freedom $df = (n_1 -1) + ( n_2 +1 )$

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

$t _{critical} = 1.760$

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject $H_o$ and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

$r^2 = \dfrac{t^2}{t^2 + df}$

$r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}$

$r^2 = \dfrac{5.040025}{5.040025+ 14}$

$r^2 = 0.2647$

7 0

3 years ago

The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0

3 years ago

A rectangular classroom has an area of 300 square feet. The length of the classroom is 5 feet longer than the width, w. Create a

weqwewe [10]

Answer:

w^2 + 5w = 300

Step-by-step explanation:

A= length x width

A =300

Width = w

length = w + 5

Therefore

300 = (w) x (w + 5)

300 = w^2 + 5w

w^2 + 5w = 300

6 0

3 years ago

Click on the area of the squarWhich equation would be used to represent the word problem below?

gogolik [260]

Answer:5.50x + 9 = 2.50x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

19m=2 and g=3, what is 3(m+3g)-(2m)

Vikki [24]

The answer is 27.1052631579 or 27.1 if you rounded "m" to .10

5 0

3 years ago