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3 years ago

Can someone please help me for the trigonometry and pythagorean theorem please?

Mathematics

2 answers:

Darya [45]3 years ago

8 0

Answer:

yes ask me as i want to help u

Dvinal [7]3 years ago

6 0

Sure I can , but please ask the question oof-

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Determine whether or not 630 is a triangular number. start with the formula t n = n ( n + 1 ) 2 and then use the quadratic formu

ziro4ka [17]

Triangular sequence = n(n + 1)/2

If 630 is a triangular number, then:

n(n + 1)/2 = 630

Then n should be a positive whole number if 630 is a triangular number.

n(n + 1)/2 = 630

n(n + 1) = 2*630

n(n + 1) = 1260

n² + n = 1260

n² + n - 1260 = 0

By trial an error note that 1260 = 35 * 36

n² + n - 1260 = 0

Replace n with 36n - 35n

n² + 36n - 35n - 1260 = 0

n(n + 36) - 35(n + 36) = 0

(n + 36)(n - 35) = 0

n + 36 = 0 or n - 35 = 0

n = 0 - 36, or n = 0 + 35

n = -36, or 35

n can not be negative.

n = 35 is valid.

Since n is a positive whole number, that means 630 is a triangular number.

So the answer is True.

7 0

3 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

7 0

3 years ago

Finally my last one :( Picture is attached below PLEASE HELP :(

Katena32 [7]

Answer:

option D is the right answer

3 0

2 years ago

Simplify the expression

Studentka2010 [4]

The answer to your question is
x^33

7 0

3 years ago

For each of the following integrals, indicate whether integration by substitution or integration by parts is more appropriate, o

Andrei [34K]

Answer:

a. ∫ xSinx dx

iii. integration by parts

u =x and dv= sinx

b. ∫ x⁴/(1+x³). dx

ii. neither

Long division is an option here before integration is done

c. ∫ x⁴. e^x³. dx

i. substitution

where u = x⁵

d. ∫x⁴ cos(x⁵). dx

i. substitution

where u = x⁵

e. ∫1/√9x+1 .dx

i. substitution

where u = 9x+1

6 0

3 years ago