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Valentin [98]
3 years ago
13

What is the equation of the circle shown in the graph? 6 9 12 36

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0
You need to add a picture in order for others to understand what you are referring to.
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The next 10 months Colin wants to save $900 for his vacation he plans to save $75 each of the first eight months how much must h
Makovka662 [10]
$300 because 300x2=600 then 75x8=300 and 600+300=900
5 0
4 years ago
There are 8 fewer tigers than lions at the zoo. There are 8 tigers at the zoo. How many lions does the zoo have?
Aleks04 [339]
Sixteen because if there are eight less tigers than lions at a zoo, then that means you add 8 to get the number of lions

8 0
4 years ago
Read 2 more answers
The table shows linear relashonsips between x and y write an equation in slope intercept form for this relashonsip!!!!!!!!!!!!!!
Alchen [17]

Answer:

y=-2x+6

Step-by-step explanation:

Slope-intercept form is given as y=mx+b, where m is slope and b is the y-intercept.

To find the slope of a line that passes through two points (x_1, x_2) and (y_1, y_2), use the slope formula:

m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}

Let:

(x_1, y_1)\implies (1, 4)\\(x_2, y_2)\implies (0, 6)

The slope of the line that passes through these two points is:

m=\frac{6-4}{0-1}=\frac{2}{-1}=-2

Now substitute m=-2 and any point to solve for b:

y=mx+b,\\6=-2(0)+b,\\6=0+b,\\b=6

Therefore, the slope-intercept form of a line that is represented by the table is \boxed{y=-2x+6}

8 0
3 years ago
7x-9y-6x+2y simplify
Pavel [41]

Answer:

x-7y

Step-by-step explanation:

7x-9y-6x+2y

Combine like terms

7x -6x    -9y +2y

x       -7y

x-7y

6 0
2 years ago
Read 2 more answers
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
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