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kifflom [539]
4 years ago
10

Solve for c. a(c−b)=d

Mathematics
1 answer:
tatiyna4 years ago
3 0

Answer:

c= ab + d/ a

Step-by-step explanation:

Let's solve for c.

a(c-b)=d

Step 1: Add ab to both sides.

-ab + ac + ab = d+ ab

ac = ab + d

Step 2: Divide both sides by a.

ac / a = ab + d / a

c = ab + d/ a

Answer:

c= ab + d/ a

Hope this helps ☝️☝☝

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(4x-1)-2(x+1)=3x-(4x+2) what do the x`s equal
Leya [2.2K]

(4x-1) - 2(x+1) = 3x - (4x+2)

Use distributive property on left side:

(4x-1) -2x -2 = 3x - (4x +2)

Simplify both sides by combining like terms:

2x -3 = -x - 2

Add 1X to both sides:

3x -3 = -2

Add 3 to both sides:

3x = 1

Divide both sides by 3:

x = 1/3

6 0
4 years ago
How do you solve these?
Murrr4er [49]

Answer:

Step-by-step explanation:

The first and only rule really is to factor these down to their primes and then apply a very simple rule

For every prime, take out 1 prime for every prime under the root sign that equals the index. The rest are thrown away.

That's very wordy. Let's try and see what it means with an example

Take sqrt(27) The index is 1/2 (square root) That means we need two threes in order to apply the rule.

sqrt(27) = sqrt(3 * 3 * 3 ) For every two primes take out 1 and throw one away.

sqrt(27) = 3 sqrt(3) You can't take out that 3rd 3.

64 = 2 * 2 *2 *2 *2 * 2

4th root 64 =  <u>2*2*2 </u><u>*2</u><u> </u>* 2 *2

for every 4th root, you get to take 1 out and throw three away.

4th root 64 = 2 fourth root (2*2)

4th root 64 = 2 fourth root (4)

- 189 = -  <u>3 * 3 * </u><u>3</u> * 7

cuberoot (- 189) = For every 3 roots, you get to pull 1 out and throw the other two away.

3 cube (- 7) is your answer.

72 = 2 * 2 * 2 * 3 * 3

cube root (72) = 2 cube root(9) You don't have enough threes to do any more than what is done.

6 0
3 years ago
What’s the answer? Plz explain.
Daniel [21]

y = (x-5) (x+6)

y = x+6


-- Clear the parentheses in the first one (multiply it out):


y = x² + x - 30


-- Look at the two equations at the same time.


y = x² + x - 30

y = x + 6


Two quantities that are both equal to the same thing (y)

must be equal to each other, so you can write


x² + x - 30 = x + 6


and THAT should be easy to solve.


-- Subtract' x ' from each side:


x² - 30 = 6


-- Add 30 to each side:


x² = 36


-- Square root each side:


x = 6

and

x = -6 .


Those are the x-coordinates of the two solutions to the

original system of equations. We don't even care about

their y-coordinates, or where exactly they are on the graph.

All we need is the x-coordinate of a the mid-point of a line

segment between them.


Do you remember how to find the mid-point of a line segment ?


-- Its x-coordinate is the average of the x-coordinates of the end points.

-- Its y-coordinate is the average of the y-coordinates of the end points.


AND ...


The average of +6 and -6 is zero !


So ... the midpoint of the two solutions is on the y-axis.

Its x-coordinate is zero.

(Choice B)

4 0
4 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Mumz [18]

x^2-8x+16=x^2-4x-4x+16=x(x-4)-4(x-4)=(x-4)(x-4)=(x-4)^2

Answer:\ (x-4)^2

4 0
4 years ago
The area of a right triangle is given by the expression:
lorasvet [3.4K]

The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u><em>Recall</em></u>:

The area of a triangle = \frac{1}{2} bh

<em><u>Given</u></em>:

Area of triangle = \frac{1}{2} (6x^2 - 7x - 3)

Length of one of the legs = 3x + 1

Therefore, it means that multiplying both legs should give us:

6x^2 - 7x - 3

To find the expression that models the other leg, divide 6x^2 - 7x - 3 by 3x + 1:

  • <em>Thus</em>:

\frac{6x^2 - 7x - 3}{3x - 1}

  • Factorize the numerator

\frac{6x^2 - 2x - 9x - 3}{3x - 1}\\\\\frac{2x(3x - 1) - 3(3x - 1)}{3x - 1}\\\\\frac{(2x- 3)(3x - 1)}{3x - 1}

  • Simplify

\frac{(2x- 3)(3x - 1)}{3x - 1} = 2x- 3

Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/20712284

6 0
2 years ago
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