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AVprozaik [17]
3 years ago
6

The track team ran a mile and a quarter during their practice. How many kilometers did the team run

Mathematics
1 answer:
AnnZ [28]3 years ago
5 0
The answer would be 2.012 km.
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X+4+3x Equivalent Expressions
melamori03 [73]

If you want to simplify the expression, combine like terms

x and 3x go together, so they make 4x.

and 4 is just 4

So, the answer is

4x + 4

3 0
3 years ago
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Help please, I'm feeling stressed out. Use the diagram below to answer the following questions. Type your answers below each que
avanturin [10]
A. points d, c, and g
B. segment FD, DG, DC, and FG. Don't forget to put a horizontal line over the letters to indicate that it is a segment
C. What are you asking?
D. Ray F G and D
6 0
2 years ago
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Gina started with the circle (x−2)2+y2=16. She translated it 4 units left and 1 unit down. Then she reduced the radius by 1 unit
olchik [2.2K]

Answer:

(x + 2)² + (y + 1)² = 9

Step-by-step explanation:

Gina started with a circle with the given equation as,

(x - 2)² + (y - 0)² = 16

Since, standard equation of a circle is,

(x - a)² + (y - b)² = r²

Here (a, b) is the center of the circle and 'r' is the radius.

Therefore, from the given equation of the circle,

Center of the circle → (2, 0)

Radius of the circle → √16 = 4 units

She translated this circle 4 units left and 1 unit down.

Rule for the new center after translation will be,

(x, y) → (x - 4, y - 1)

(2, 0) → (2 - 4, 0 - 1)

         → (-2, -1)

Coordinates of the new center → (-2, -1)

Then she reduced the radius by 1 units.

Therefore, radius of the new circle = 4 - 1 = 3 units

Now we substitute these values in the standard equation of the circle to get the equation of the new circle.

(x + 2)² + (y + 1)² = 3²

(x + 2)² + (y + 1)² = 9

5 0
3 years ago
How could you determine one-fourth the length of a segment
Elza [17]
Divide the length of the segment by 4 
8 0
3 years ago
How do I Simplify i^54
yanalaym [24]

Answer:

i^{54}=-1

Step-by-step explanation:

First, recall the 4 basic imaginary exponents:

i^1=i \text{, }i^2=-1\text{, }i^3=-1\text{ and } i^4=1

So, we want to find:

i^{54}

This is the same as:

=i^{52}\cdot i^2

52 is 4 times 13. Thus:

=(i^4)^{13}\cdot i^2

Since we know that i to the fourth is 1:

=(1)^{13}\cdot i^2

Simplify:

=i^2

And this equals:

=-1

So:

i^{54}=-1

6 0
3 years ago
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