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2 years ago

5.

Mathematics

2 answers:

emmasim [6.3K]2 years ago

8 0

Answer:

B. x = −1

Step-by-step explanation:

In the graph, the vertex of the parabola hits point (-1,-2). Therefore, the axis of symmetry is x = -1. It is not y = -2, since the parabola opens vertically, not horizontally.

olga2289 [7]2 years ago

3 0

Answer is C x=1 because that’s the middle of it.

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Jane is is charge of making a banner for the basketball game this Saturday. She measures how long the banner is before painting

RSB [31]

Answer:

The measurement which Jane finds to be 10 meters is the length of the banner.

Step-by-step explanation:

The measurement of 10 meters which Jane found after measuring how long the banner is before painting is the LENGTH of the banner.

This is clear from the unit of what she finds (meters). It only indicates the measurement of one part of the banner, even though a banner has two parts, the length and width.

It is possible to find the AREA, or PERIMETER, or LENGTH.

But what she finds is the LENGTH of the banner. If it was Area or Perimeter, the unit would have been square meters.

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3 years ago

Eighteen less than 9 times a number is the same as 14 more than the number.<br> Comply the equation

frez [133]

Answer:

x=4

Step-by-step explanation:

9x-18 = x+14

9×-× = 14+18

8× = 32

X = 4

3 0

3 years ago

Please help me find the value of x! Thank you!

Arisa [49]

Answer:

there is no value its letter

Step-by-step explanation:

there is no value to a letter duh

3 0

2 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$