1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nika2105 [10]
3 years ago
5

Write 0.000700804 in scientific notation please

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

Multiply the 0.00070080 by 10, 4 times, making it a 7.008. When you multiply each time by 10 it moves the decimal point to the right one time. To keep the number the same you put x10 to the 4th power next to the 7.008. This makes your answer 7.008x10 to the negative 4th power.

Hope I could help! :)


You might be interested in
Solve for x in the equation x²-12x+59=0
lyudmila [28]

{x}^{2}  - 12x + 59 = 0 \\  {x}^{2}  - 12x + 36 + 23 = 0 \\  {x}^{2}  - 12x + 36 =  - 23 \\  {(x - 6)}^{2}  =  - 23 \\ x - 6 =  +  -  \sqrt{ - 23}  =  +  - i \sqrt{23}  \\ x = 6 +  - i \sqrt{23}

mean

x = 6 + i \sqrt{23}

or

x = 6 - i \sqrt{23}

7 0
3 years ago
Read 2 more answers
What is the mode of the data?<br> A) 9<br><br> B) 12 <br><br> C)26<br><br> D) 35
Flauer [41]

Answer:

c)26 or positive and negative

5 0
3 years ago
In Jamie's town, there are 42,812 adults and 12,358 children. About how many more adults than children are in Jamie's town?
Kipish [7]

Answer:

30454

Step-by-step explanation:

subtraction on a calculator

42812-12358=30454

4 0
3 years ago
Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices
Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt

Where P, Q are scalar functions

We want to compute

\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths \large C_1,C_2,C_3,C_4 which represents the sides of the rectangle.

\large C_1 is the line segment from (0,0) to (5,0)

\large C_2 is the line segment from (5,0) to (5,1)

\large C_3 is the line segment from (5,1) to (0,1)

\large C_4 is the line segment from (0,1) to (0,0)

Then

\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize \large C_1 as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

\large \displaystyle\int_{C_1}xydx+x^2dy=0

 Now the second integral. We parametrize \large C_2 as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25

The third integral. We parametrize \large C_3 as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2

The fourth integral. We parametrize \large C_4 as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

\large \displaystyle\int_{C_4}xydx+x^2dy=0

So

\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2

Now, let us compute the value using Green's theorem.

According with this theorem

\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx

where A is the interior of the rectangle.

so A={(x,y) |  0≤ x≤ 5,  0≤ y≤ 1}

We have

\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x

so

\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2

3 0
3 years ago
Which of the following tables represents a proportional relationship?
algol13

Answer:

You’re right!

Step-by-step explanation:

It IS 3, heres why:

it follows the same rule each time:

2X=Y

1 times 2 is 2

6 times 2 is 12

11 times 2 is 22

16 times 2 is 36

thats proportionate! :D

i hope this helps!

6 0
3 years ago
Read 2 more answers
Other questions:
  • 5L/s=__________kl/min
    12·1 answer
  • 60 time what equals to 120
    6·2 answers
  • Please help I already did the hint part but I’m not sure how to get the width or I don’t even know
    12·2 answers
  • PLSS HELP<br> look at pic
    13·1 answer
  • What is the solution to this system of equations?<br> x = 12 − y<br> 2x + 3y = 29
    11·2 answers
  • Uehehejjdjdjejjejejjdjdjejejejejejjejejejeejjd
    8·2 answers
  • Use partial products and the distributive property to calculate the product.<br> 300 x 41.9
    15·1 answer
  • Mr. Ramone brought home 1/2 of an apple pie from work. He wants to share the apple pie equally among six friends. What is the a
    15·1 answer
  • 1, 10, 100, 1000<br> Common Difference?<br> Difference
    10·1 answer
  • Please someone help me ITS URGENT I WILL BRAINLIST UUUU AND MARK U 5 star!! ANYONE WHO IS GOOD AT MATHS?..
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!