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horrorfan [7]
2 years ago
6

Simplify (r^4)(-12 r^7)

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
8 0

12r^11. hope this helps.

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Multiply (2 -10i) (-5 + 3i) Show each step for credit!
jonny [76]

Answer:

The answer is

<h2>20 + 56i</h2>

Step-by-step explanation:

(2 -10i) (-5 + 3i)

Using FOIL multiply each term in the first bracket by the terms in the second <u>bracket</u>

That's

2(-5) + 2(3i) - 10i(-5) - 10i(3i)

<u>Multiply the numbers and simplify</u>

We have

- 10 + 6i + 50i - 30i²

From the rules of imaginary numbers

<h3>i² = - 1</h3>

So we have

- 10 + 56i - 30(- 1)

- 10 + 56i + 30

Simplify

30 - 10 + 56i

We have the final answer as

<h3>20 + 56i</h3>

Hope this helps you

5 0
2 years ago
Find the slope of every line that is perpendicular<br> to this one
ArbitrLikvidat [17]

Answer:

1

Step-by-step explanation:

The slope of this line is -1 or -1/1, and to find the perpendicular slope you find the opposite of the reciprocal, which in this case would be 1/1 which simplifies to 1.

7 0
3 years ago
What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of .
hjlf
The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
<span>x - 3y - 7 = 0</span>
4 0
2 years ago
Read 2 more answers
Use the graphing calculator to locate the solutions of this system of equations: y = x2 + x – 2 y = –x + 1
bonufazy [111]

Answer:

(–3, 4) and (1,0)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
2 years ago
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