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3 years ago

Use the recursive formula to answer the question.

Mathematics

1 answer:

Oliga [24]3 years ago

7 0

Answer:

Step-by-step explanation:

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Use the formula SA=6s2 , where SA is the surface area and s is the edge length of the cube, to solve this problem.

Irina-Kira [14]

Using the SA formula you'll have to substitute in the edge length for s.

SA = 6(312)²
SA = 584064

The surface area is 584,064 feet²

Hope this helps :)

3 0

3 years ago

Read 2 more answers

Please,someone can help me this question!!!

Anvisha [2.4K]

Answer:

x=126°, y=234°

Step-by-step explanation:

B altrenates A

180-54=126, x=126°

D is 180°, 54+180=234°

3 0

3 years ago

A letter is drawn at random from the word MATHEMATICS .Find the probability that the letter is vowel given that it appears only

Lapatulllka [165]

It should be 1 over 2 or 1 over 11 but im pretty sure its the first one I picked

5 0

3 years ago

in the following ordinary annuity interest is compounded with each payment and the payment is made at the end of the compounding

RSB [31]

Answer: $59313.58

Step-by-step explanation:

Formula to find the accumulated amount of the annuity is given by :-

$FV=A(\frac{(1+\frac{r}{m})^{mt})-1}{\frac{r}{m}})$

, where A is the annuity payment deposit, r is annual interest rate , t is time in years and m is number of periods.

Given : m= $2000 ; m= 1 [∵ its annual] ; t= 10 years ; r= 0.06

Now substitute all these value in the formula , we get

$FV=(4500)(\frac{(1+\frac{0.06}{1})^{1\times10})-1}{\frac{0.06}{1}})$

⇒ $FV=(4500)(\frac{(1.06)^{10})-1}{0.06})$

⇒ $FV=(4500)(\frac{0.79084769654}{0.06})$

⇒ $FV=(4500)(13.1807949423)$

⇒ $FV=59313.5772407\approx59313.58 \ \ \text{ [Rounded to the nearest cent]}$

Hence, the accumulated amount of the annuity= $59313.58

8 0

3 years ago

---<br> What is the slope of the equation y=5/4 x -7/4

taurus [48]

Answer:

5/4

Step-by-step explanation:

The slope intercept form for a linear equation is y = mx + b. The variable's (x) coefficient, which is represented as m, is the slope of any linear equation.

5 0

3 years ago