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nalin [4]
2 years ago
7

C) P, Q, and R are prime numbers such that 3 * P + 7 * Q + 15 * R = 102. What is Q?

Mathematics
2 answers:
wolverine [178]2 years ago
6 0

Answer:

Q = 3‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ 

Good Luck!!

lana66690 [7]2 years ago
5 0

Answer:

Q = 3

Step-by-step explanation:

3 * P + 7 * Q + 15 * R = 102

7Q = 102 - 3P - 15R

Q = (102 - 3P - 15R)/7

Try P = 2; R = 3

Q = 51/7 not an integer

Try P = 2; R = 5

Q = 21/7 = 3

Solution: P = 2; Q = 3; R = 5

Answer: Q = 3

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It is not accurate because only information from teenagers was used to make the claim.

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This is the correct answer because they only used the data that pertained to their teen readers. The magazine does not only have teen readers, but has many ages. The statement regarding internet use generalizes it to all readers, not just teens, therefore making its claim inaccurate because the scope of inference is not appropriate for the claim that was made.

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Which polynomial is written in ascending order?
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What are the options for this question?
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3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
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Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

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Answer:

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Step-by-step explanation:

8 0
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