3 years ago

Find the sum of the integers (-12)+7

Mathematics

2 answers:

Alex73 [517]3 years ago

8 0

Answer:

<h2>The answer will be <u><em>-5</em></u></h2>

Step-by-step explanation:

Hope this helped...

Fynjy0 [20]3 years ago

6 0

Answer:

-5 is the answer Very easy

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Angle 1 and angle 2 are vertical angles.

emmasim [6.3K]

Answer:

<1 = 93 (vertical opposite angle are equal)

Step-by-step explanation:

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3 years ago

What is m 2DEC?<br> In square ABCD, we know:<br> AB = 6 and BE = 4.2

Alex787 [66]

Answer:

As mentioned ABCD is a square

So <DEC is always 90 degree

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3 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

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1 year ago

Did I get these all right

Leviafan [203]

Yep! They are all right! Great job, could write a bit better.... sorry

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3 years ago

What's the value of this expression ? 40-(3x2)x6

natita [175]

4

40-(3x2)x6
40-6x6
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3 years ago

Read 2 more answers