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Vsevolod [243]
4 years ago
5

Last season a baseball play hit 48 home runs. So far this season he has hit 30 home runs. The number of home runs he has hit so

far this season is what percent of the number of home runs he hit last season?
Mathematics
1 answer:
Vanyuwa [196]4 years ago
6 0

The number of home runs he has hit so far this season is 62.5 % of the number of home runs he hit last season

<em><u>Solution:</u></em>

Given that,

Number of home runs hit last season = 48

Number of home runs hit so far this season = 30

To find: The number of home runs he has hit so far this season is what percent of the number of home runs he hit last season

Let "x" be the required percent

Then, according to above statement, we can say,

30 is what percent of 48

30 = x % of 48

30 = \frac{x}{100} \times 48\\\\30 = 0.01x \times 48\\\\0.01x = \frac{30}{48}\\\\0.01x = 0.625\\\\\text{Divide both sides of both equation by 0.01 }\\\\x = 62.5

Thus number of home runs he has hit so far this season is 62.5 % of the number of home runs he hit last season

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Step-by-step explanation:

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We can factorize the difference of squared terms like this:

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Lets prove it:

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(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)

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Answer:

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Answer:

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