$-\dfrac{5}{8}+\dfrac{1}{4}=\dfrac{1}{4}+\left(-\dfrac{5}{8}\right)=\dfrac{1}{4}-\dfrac{5}{8}\\\\\text{find LCD:}\\\\8=2\cdot4,\ \text{therefore. LCD(4, 8) = 8}\\\\\dfrac{1}{4}=\dfrac{1\cdot2}{4\cdot2}=\dfrac{2}{8}\\\\\text{continuing}\\\\=\dfrac{2}{8}-\dfrac{5}{8}=\dfrac{2-5}{8}=-\dfrac{3}{8}$

4 0

2 years ago

A young boy let’s out 30 feet of string on his kite. If the angle of elevation from the boy to his kite is 27”, how high is the

const2013 [10]

Answer:

The height of the kite from the ground is 13.617 feet

Step-by-step explanation:

Given as :

The measure of the string = 30 feet

The angle of elevation from the boy to his kite = 27°

Let the height of the kite from ground = H feet

So, From Triangle

Sin angle = $\dfrac{\textrm perpendicular}{\textrm Hypotenuse}$

Or, Sin 27° = $\dfrac{\textrm H}{\textrm 30}$

or, H = 30 × Sin 27°

I.e H = 30 × 0.4539

∴ H = 13.617 feet

Hence the height of the kite from the ground is 13.617 feet Answer

7 0

2 years ago