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valentina_108 [34]

3 years ago

9

A half of a class and a half of a student got A on a test. If yet another student got an A, then two-thirds of the class would h

ave an A for the test! How many students are there in that class? Please Help!

1 answer:

Cerrena [4.2K]3 years ago

6 0

Answer:

21

Step-by-step explanation:

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Need help with #1 #4 #7 plz giving 15 points

valentina_108 [34]

Answer:

Q1: p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $$ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{8} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{3}$

We solve this taking LCM.

We get: $\frac{-p - 24}{3} = 3$

$\implies - p - 24 = 9$

$\implies \textbf{p} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 33}$

Q4: $\frac{\textbf{d}}{\textbf{11}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{4} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13}$

Again we proceed like Q1 by taking LCM.

We get: $\frac{d - 44}{11} = - 13$

$\implies d - 44 = - 13 \times 11 = - 143$

$\implies d = - 143 + 44$

$\implies \textbf{d} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 99}$

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$\implies 5t - 4t = - 1 - 12$

$\implies (5 -4)t = - 13$

$\implies \textbf{t} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{- 13}$

Hence, the answer.

7 0

3 years ago

What is the square root of 81

Kay [80]

The square root of 81 is 9
Your answer is <em>9
</em>Work:
9 x 9 = 81

7 0

3 years ago

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Y’all I need help!! I accidentally deleted my downloads, history, bookmarks on chrome on my computer is there any way I can rest

8090 [49]

Answer:

Nope.

Step-by-step explanation:

there is no way you just "deleted" all of those. That will never happen because it takes forever to remove bookmarks and delete downloads. Just sayin

4 0

3 years ago

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Find the f^-1(x) and it’s domain

borishaifa [10]

Answer:

$f^{-1}(x) = (x + 8)^2$

$x \ge -8$

Step-by-step explanation:

Given

$f(x) = \sqrt x - 8$

Solving (a): $f^{-1}(x)$

We have:

$f(x) = \sqrt x - 8$

Express f(x) as y

$y = \sqrt x - 8$

Swap x and y

$x = \sqrt y - 8$

Add 8 to $both\ sides$

$x + 8 = \sqrt y - 8 + 8$

$x + 8 = \sqrt y$

Square both sides

$(x + 8)^2 = y$

Rewrite as:

$y = (x + 8)^2$

Express y as: $f^{-1}(x)$

$f^{-1}(x) = (x + 8)^2$

To determine the domain, we have:

The original function is $f(x) = \sqrt x - 8$

The range of this is: $f(x) \ge -8$

The $domain$ of the $inverse$ function is the $range$ of the $original$ function.

<em>Hence, the domain is:</em>

$x \ge -8$

3 0

3 years ago

7. carmen estimates that deductions from his gross pay will be 25%. assuming the weekly gross pay is $229.22, carmen can expect

daser333 [38]

nececito tus puntos perdon

8 0

3 years ago

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