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inn [45]
2 years ago
9

What is the value of x?

Mathematics
1 answer:
pishuonlain [190]2 years ago
6 0

Answer:

jhg hstu35kk4t6ek

3tnk63e6oktelrt

Step-by-step explanation:

4n5kdti3eo5

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Please Help 6-10 or just one of them
Free_Kalibri [48]

Answer:

6) 20

7) I think is 2.5 (im not sure)

8) 7

Step-by-step explanation:

6) (5x+9)+(3x+11)=180

    8x+20=180

         -20   -20

          8x=160

Divide 8 on each side

            x=20

7) (17x+1)=(20x-14)

   17x+15 =20x

   +17         +17

     15 = 37x

divide 15 on each side

X=2.5

8) (3x+3)+(10-4)=90

    (3x)+(10x-1)

      13x-`1=90

            +1   +1

         13x=91

Divide 13 on each side

x=7

5 0
2 years ago
If sydney answer 15 questions in the first section correctly what is the minimum number of questions she must have answered corr
Mandarinka [93]

Answer:

8 Is correct on EDGE 2020

Step-by-step explanation:

Just took the test and got it right

3 0
3 years ago
For what values of x will the function f(x) = 3x² + 13x - 10 equal zero?
Oduvanchick [21]

Answer:

x = - 5 , x = \frac{2}{3}

Step-by-step explanation:

the values of x that make f(x) zero are the zeros

to find the zeros let f(x) = 0 , that is

3x² + 13x - 10 = 0

consider the factors of the product of  the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 10 = - 30 and sum = + 13

the factors are + 15 and - 2

use these factors to split the x- term

3x² + 15x - 2x - 10 = 0 ( factor the first/second and third/fourth terms )

3x(x + 5) - 2(x + 5) = 0 ← factor out (x + 5) from each term

(x + 5)(3x - 2) = 0

equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = \frac{2}{3}

4 0
2 years ago
How do you solve 2x^2+x=-1?
Olin [163]

Answer:

x = 0.2

Step-by-step explanation:

2x^2+x=-1

4x + x = -1

5x = -1

divide by 5

5x/5 = -1/5

x = 0.2

3 0
3 years ago
Solve using inverse operations 83+q=125; q=
Vilka [71]

Answer:

42

Step-by-step explanation:

83+q=125

q=125-83

q=42

3 0
2 years ago
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