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madam [21]
2 years ago
6

Evaluate a - b if a = 5 and b = 7.

Mathematics
2 answers:
maxonik [38]2 years ago
8 0

Answer:

5 - 7

Step-by-step explanation:

a - b

5 - 7 = -2

Alenkinab [10]2 years ago
3 0
5-7.
a = 5
b = 7
a - b = 5 - 7
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What is -(1)<br>Please help me.
KatRina [158]
It Is Just -1.
The Parenthesis Are All Simplified, And The Subtraction Sign Changes It To Negative. So, 1 Changed To Negative Is -1. <span />
8 0
3 years ago
Riley invested $1,000 in savings bonds. If bonds earn 6.75% interest compounded semi-annually, how much will riley earn in 15 ye
lara31 [8.8K]

Answer:

$2,706.86

Step-by-step explanation:

8 0
2 years ago
There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an
vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

C =100 -50\\C= 50\ students

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

D =110 -50\\C= 60\ students

The number of students that have taken a course in either calculus or discrete mathematics is:

E = C+D = 50+60\\E= 110\ students

7 0
3 years ago
Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da
Bess [88]
A system of equations is:
B ) 
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.

6 0
2 years ago
Read 2 more answers
For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the
AfilCa [17]

<u>ANSWER</u>

The zeros are x=-5,x=0,x=5


EXPLANATION

Given;

f(x)=x^4-25x^2.


We can rewrite the function as


f(x)=x^2(x^2-25)


\Rightarrow f(x)=x^2(x^2-5^2)


\Rightarrow f(x)=x^2(x-5)(x+5)



The zeros are found by equating the function to zero.


\Rightarrow x^2(x-5)(x+5)=0


\Rightarrow (x-5)=0

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=5


Or

\Rightarrow (x+5)=0


The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=-5


Or


\Rightarrow x^2=0


This last root has a multiplicity of 2.

That is

x=0 repeats two times.


Since the multiplicity is even, the graph touches the x-axis at the point x=0.



See graph.









5 0
3 years ago
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