Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get
(4ax-10bx)+(6ay-15by)
Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)
Not sure how to explain this step in words but so do this
(2x+3y)(2a-5b)
The solution is (2x+3y)(2a-5b)
First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
The total possibility that the head and even no on dice appears is 3. and total possible choice are 12 {head ---> (1,2,3,4,5,6) & tail ---> (1,2,3,4,5,6)}. so the probability is 3/12= 1/4.
C: 1/4
Hey there!
Okay let's get cracking :D
The equation is.... (2x/3) - 6 = 9
2x/3 = 15
2x = 45
<u>x = 22.5</u><u /> <----- And that is your answer!
I hope it helped!
<u>Please vote for me as Brainliest if there is a second answer!</u>
, we have
