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amid [387]
3 years ago
9

Find the dimensions of a right-circular cylinder that is open on the top and closed on the bottom, so that the can holds 1 liter

and uses the least amount of material? ...?
Mathematics
1 answer:
anzhelika [568]3 years ago
5 0
Volume of cylinder:
V = πr²h
The desired volume is 1 Liter = 1000 cm³
1000 = πr²h
h = 1000/πr²

Surface area of cylinder:
S.A = 2πr² + 2πr²h
We substitute the value of h from the first equation:
S.A = 2πr² + 2πr(1/πr²)
S.A = 2πr² + 2/r
Now, to minimize surface area, we differentiate the expression with respect to r and equate to 0.
0 = 4πr - 1000/r²
4πr³ - 1000 = 0
r = 4.3 cm
h = 17.2 cm
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Nastasia [14]

The area formula of a circle is r^{2} × π.

With that being said, we can solve both problems!

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(21 x 21) x π

(441) x π

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1385.44236023

Which rounded to the nearest tenth is 1385.4. Therefore, the area of the porthole is 1385.4 centimetres.

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