Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
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ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
C and D.............................
Answer:
g(-3) = -13
Step-by-step explanation:
Plug in -3 for n in the equation:
g(n) = 3n - 4
g(-3) = 3(-3) - 4
Remember to follow PEMDAS. First, multiply, then subtract:
g(-3) = 3 * -3 = -9
g(-3) = -9 - 4
g(-3) = -13
-13 is your answer for g(-3).
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Answer:
Fill in the missing information for each rectangle in the table below
Step-by-step explanation:
salamat sa points
