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Anna35 [415]
3 years ago
5

How do you simplify 7x×4y×2y^2

Mathematics
1 answer:
belka [17]3 years ago
6 0
The answer is: 56xy³
_______________________________
Explanation:
_______________________________
Find the "like terms"; which are: 
_______________________________
"4y" and "2y<span>²"
_______________________________
The remaining term is: "7x".
_____________________________________
The problem is a "multiplication problem" :
___________________________________________
7x * 4y * </span>2y² ; so start by multiplying the "like terms" :
<span>___________________________________________
4y * 2y</span>² = 8y<span>³
____________________________________________
Then the remaining term is "7x";
        so, multiply that by our obtained value: "</span>8y³ " :
_____________________________________________
7x * 8y³  = 56xy³ ; which is our answer:
___________________
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Solve the expression x^2-100=0
enot [183]

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± \sqrt{100} ← note plus or minus, hence

x = ± 10

6 0
3 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
3 years ago
Mr.Chen left $45,000 to his aunt when he died. This was 5% of his total worth. a) how much was Mr.Chen worth when he died? Show
marysya [2.9K]

A) Mr Chen was worth:

45,000/5 = 9,000

9,000 x 100 = 900,000

The answer is 900,00

You can also write this as an equation.

3 0
3 years ago
Leanne has a gas card that has $150 on it. She spends $25 a week on gas. Write and recursive rule that represents the amount of
Tems11 [23]

In this question, it is given that

Leanne has a gas card that has $150 on it. She spends $25 a week on gas.

And we have to Write a recursive rule that represents the amount of money she has on her gas card after the first week  .

Recursive rule shows the relationship between previous value and the current value .

And here, the recursive rule is

a_{n} = a_{n-1}-25n

Where a(n-1) is the initial amount which is $150 . And a(n) is the amount after n week .

So for n=1, that is amount in the card after 1 week, we will get

a_{1} = a_{1-1} -25(1)&#10;\\&#10;a_{1} = a_{0} -25&#10;\\&#10;a_{1} = 150 -25&#10;\\&#10;a_{1} = $125

And that's the amount remaining in the card after 1 week .

5 0
3 years ago
A negative number plus a positive number is a negative number.
ipn [44]

Answer:

Sometimes

Step-by-step explanation:

Examples:

-5 + 10 = 5   FALSE

-10 + 5 = -5  TRUE

7 0
3 years ago
Read 2 more answers
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