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boyakko [2]
4 years ago
6

Three pizzas are being split amongst friends. Everyone will get 1/4 of a pizza. How many friends can eat pizza? Help ASAP, ill g

ive brainlist to first answer
Mathematics
2 answers:
suter [353]4 years ago
8 0

Answer:

12 people

Step-by-step explanation:

If everyone is getting 1/4 of the pizza then that means there are 4 slices in each pizza

tatuchka [14]4 years ago
5 0

Answer:

12 friends

Step-by-step explanation:

If we have 3 pizzas, each cut into slices of \frac{1}{4}, then we have a total of 3 \div \frac{1}{4} = 3\cdot\frac{4}{1} = 12 slices.

This means that 12 friends can share the 3 pizzas.

Hope this helped!

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Aleksandr [31]

Answer:

I don't no sorry please bro sorry

4 0
3 years ago
SUPER URGENT: Complete the general form of the equation of a sinusoidal function having an amplitude of 6, a period of 2pi/3, an
mel-nik [20]

Answer:

y = 6·sin(3·(x - 1)) + c

Step-by-step explanation:

The general form of an equation for a sinusoidal function is presented ad follows;

y = a·sin(b·(x - h) + c

Where;

a = The amplitude of the equation

T = The period = 2·π/b

h = The phase shift

c = The vertical shift

From the question, we have;

a = 6,

2·π/3 = 2·π/b

∴ b = 3

h = 1

We get;

y = 6·sin(3·(x - 1)) + c.

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3 years ago
Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}

(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

converges by comparison to the convergent <em>p</em>-series,

\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

converges absolutely, since

\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

5 0
3 years ago
− ( − ) = what is x
skelet666 [1.2K]

Answer:

There is no x the equation so there is really no answer for x

Step-by-step explanation:

5 0
3 years ago
Solve -2 (t- 1) = 18
Alla [95]

Answer:

t=-8

Step-by-step explanation:

-2 (t- 1) = 18

Divide each side by -2

-2 (t- 1)/-2 = 18/-2

t-1 = -9

Add 1 to each side

t-1+1 = -9+1

t = -8

5 0
3 years ago
Read 2 more answers
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