<u>Options</u>
- Counting rule for permutations
- Counting rule for multiple-step experiments
- Counting rule for combinations
- Counting rule for independent events
Answer:
(C)Counting rule for combinations
Step-by-step explanation:
When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.
- When the order of selection is important, we use permutation.
- However, whenever the order of selection is not important, we use combination.
Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.
Answer:
X density = fXpxq and
Y" =InpXq
Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"
fX = In
And PXq =pxq
Thus replacing x with y,
PXq = pyq
(a) Hence the density of Y is FYpyq
(b) at p0, fYpyq =fYp0q= 0
At 5s, FYpyq =5
Answer:

Step-by-step explanation:
Hello there!
We can solve for x using law of sines
As we can see in the image a side length divided by sin ( its opposite angle) = a different side length divided by sin ( its opposite angle)
So we can use this equation to solve for x

Our objective is to isolate the variable using inverse operations so to get rid of sin (65) we multiply each side by sin (65)

we're left with

assuming we have to round the answer would be 33.18 or 33.2
Answer:
x y
-2 0
0 2
Slope: 1
y-intercept = 2 ( 0, 2 )
Hope this helped!
Have a supercalifragilisticexpialidocious day!
Answer: c. 8!
Step-by-step explanation:
We know , that if we line up n things , then the total number of ways to arrange n things in a line is given by :-
( in words :- n factorial)
Therefore , the number of ways 8 cars can be lined up at a toll booth would be 8! .
Hence, the correct answer is c. 8! .
Alternatively , we also use multiplicative principle,
If we line up 8 cars , first we fix one car , then the number of choices for the next place will be 7 , after that we fix second car ,then the number of choices for the next place will be 6 , and so on..
So , the total number of ways to line up 8 cars = 8 x 7 x 6 x 5 x 4 x 3 x 2 x1 = 8!
Hence, the correct answer is c. 8! .