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kolezko [41]
2 years ago
6

What is the distance between points M and N?

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
6 0

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

<h3>How to determine the distance between two points</h3>

In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:

\cos L = \frac{(19.6\,m)^{2}-(14.8\,m)^{2}-(21.4\,m)^{2}}{-2\cdot (14.8\,m)\cdot (21.4\,m)}

L ≈ 62.464°

Then, we get the distance between points M and N by the law of the cosine once again:

MN = \sqrt{(7.4\,m)^{2}+(10.7\,m)^{2}-2\cdot (7.4\,m)\cdot (10.7\,m)\cdot \cos 62.464^{\circ}}

MN ≈ 9.8 m

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

To learn more on triangles: brainly.com/question/2773823

#SPJ1

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"The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N obj
Liula [17]

<u>Options</u>

  • Counting rule for permutations
  • Counting rule for multiple-step experiments
  • Counting rule for combinations
  • Counting rule for independent events

Answer:

(C)Counting rule for combinations

Step-by-step explanation:

When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.

  • When the order of selection is important, we use permutation.
  • However, whenever the order of selection is not important, we use combination.

Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.

7 0
3 years ago
Let X be a positive continuous random variable with density fXpxq. Let Y " lnpXq. (a) Find the density fY pyq of Y in terms of t
salantis [7]

Answer:

X density = fXpxq and

Y" =InpXq

Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"

fX = In

And PXq =pxq

Thus replacing x with y,

PXq = pyq

(a) Hence the density of Y is FYpyq

(b) at p0, fYpyq =fYp0q= 0

At 5s, FYpyq =5

7 0
3 years ago
Read 2 more answers
Find x <br> Plz help me !!!
mel-nik [20]

Answer:

\Huge\boxed{x=33.2}

Step-by-step explanation:

Hello there!

We can solve for x using law of sines

As we can see in the image a side length divided by sin ( its opposite angle) = a different side length divided by sin ( its opposite angle)

So we can use this equation to solve for x

\frac{21}{sin(35)} =\frac{x}{sin(65)}

Our objective is to isolate the variable using inverse operations so to get rid of sin (65) we multiply each side by sin (65)

\frac{x}{sin(65)} sin(65)=x\\\\\frac{21}{sin(35)} sin(65)=\frac{21sin(65)}{sin(35)}

we're left with

x=\frac{21sin(65)}{sin(35)}\\x=33.18208755

assuming we have to round the answer would be 33.18 or 33.2

7 0
3 years ago
What is the table of values for y=x+2
Marta_Voda [28]

Answer:

x        y

-2       0

0       2

Slope: 1

y-intercept = 2 ( 0, 2 )

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0
3 years ago
The number of ways 8 cars can be lined up at a toll booth would be computed from
stepladder [879]

Answer: c. 8!

Step-by-step explanation:

We know , that if we line up n things , then the total number of ways to arrange n things in a line is given by :-

n! ( in words :- n factorial)

Therefore , the number of ways 8 cars can be lined up at a toll booth would be 8! .

Hence, the correct answer is c. 8! .

Alternatively , we also use multiplicative principle,

If we line up 8 cars , first we fix one car , then the number of choices for the next place will be 7 , after that we fix second car ,then the number of choices for the next place will be 6 , and so on..

So , the total number of ways to line up 8 cars = 8 x 7 x 6 x 5 x 4 x 3 x 2 x1 = 8!

Hence, the correct answer is c. 8! .

5 0
3 years ago
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