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Citrus2011 [14]
3 years ago
5

Suppose the government imposes a price floor of $28 in this market. If the sellers with the lowest cost are the ones who sell th

e good and the government does not purchase any excess units produced, then total surplus will be

Business
1 answer:
Anit [1.1K]3 years ago
4 0

Answer:

$1120

Explanation:

The chart of the question is in the below image.

Consumer surplus is the area above the price line and below the demand curve whereas producer surplus is the area below the price line and above the supply curve. These areas can be calculated by using the formula of area of a triangle which is

If the government imposed a price floor of $28 then the consumer surplus will be:

A = (1/2)×$40×($48 -$28)

A = $400

The producer surplus = ($28 -$20)×$40 + (1/2)×($20-$0)×($40 -$0)

The producer surplus = $8× $40 + $400 = $320+$400 = $720

Total surplus can be calculated as:

Total Surplus = Consumer surplus + Producer Surplus

Total Surplus = $400 + $720 = $1120

Total Surplus is $1120

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The amount for gross trade account receivable is $520

The amount for bad debt expense is $144

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The gross amount receivable is total receivable amount from the sales made. In the given scenario the amount receivable for the year is $443 plus the provisions made at the end of the year. The gross receivable is $520.

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3 years ago
Assuming P≥0, suppose that a population develops according to the logistic equation ????P/????????=0.07P−0.00014P2 where ???? is
Natasha2012 [34]

Answer:

A complete description of the problem and solutions to each point are given below.

Explanation:

The Logistic Growth model of a population is defined as follows:

                                   dP/dt = kP (1 - P/M) (1)

Where:

dP/dt is the population growth rate.

k is the maximal individual growth rate for a given population

P is the number of individual in the population

M= carrying capacity of the population.

In the problem this first order derivative ecuation is given by

                               dP/dt= 0,07P - 0,00014P² (2)

So, we can factorize ecuation (1) and compare it with (2) to find the carryng capacity and k value (questions 1 and 2).

                                        kP (1 - P/M) = 0,07P - 0,00014P²

                                        kP - (k/M)P² = 0,07P - 0,00014P²

Here kP = 0,07P ⇒ k = 0,07 (answer to question 2)

Then, (k/M)P² = 0,00014P²⇒ (k/M) = 0,00014 and given that k= 0,07

⇒ 0,07/M = 0,00014 ⇒ M = 0,07/0,00014 ⇒ M=500 (answer to question 1)

Finally to find for which values of P is the population increasing/decreasing, we have to find the values at which dP/dt is zero. Analyzing the equation as a quadratic function (applying Baskara´s equation) we find that the values at which dP/dt is zero are P= 0 and P = -1.

x = [-0,07 ± √(0,07²)]/ 0,14 ⇒ x=  [-0,07 ± 0,07)]/ 0,14 ⇒ x = 0 and x= -1.

Then the vertex here is P = -0,5.

Now we can state that for P greater than - 0,5 the population is decreasimg (question 4), while for values from -∞ to - 0,5 the population is increasing (question 3).

Summarizing, given the first order derivative, the carrying capacity of the population is 500, the value of k is 0,07, the values of P for which dP/dt is positive (incresing population) are those comprised in the range (-∞, -0,5) and those for which the population is decreasing are (-0,5,∞).

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3 years ago
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What is a budget, how does it work, and how can it help you?
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Explanation:

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Answer:

Closing work in progress using FIFO is $1,282.

Explanation:

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